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3 years ago

What is the power produced by a light bulb with a voltage of 120 volts and a current of 0.045 amps? PLEASE HELP I HAVE 5 MINUTES

Chemistry

2 answers:

Artyom0805 [142]3 years ago

8 0

The answer is 5.4! I found it on a an online calculator!

GuDViN [60]3 years ago

7 0

Answer : The power produced by light bulb is, 5.4 watts

Solution : Given,

Voltage = 120 V

Current = 0.045 A

Formula used :

$P=V\times I$

where,

P = power produced by light bulb

V = voltage

I = current

Now put all the given values in the above formula, we get the power produced by the light bulb.

$P=(120V)\times (0.045A)=5.4watts$

Therefore, the power produced by light bulb is, 5.4 watts

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How many molecules are there in 8.00 grams of glucose, C6H12O6

beks73 [17]

Answer:

molecules C6H12O6 = 2.674 E22 molecules.

Explanation:

from periodic table:

⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))

⇒ Mw C6H12O6 = 180.156 g/mol

⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6

∴ mol ≡ 6.022 E23 molecules

⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)

⇒ molecules C6H12O6 = 2.674 E22 molecules

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3 years ago

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svlad2 [7]

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Explanation:

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3 years ago

How many liters of water can be formed if 1.65 liters of ethylene are consumed

alexandr1967 [171]

Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

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According to equation,

22.4 L (1 mole) C₂H₄ reacts completely to produce = 44.8 L (2 moles) of H₂O

So,

1.65 L of C₂H₄ on complete reaction will produce = X L of H₂O

Solving for X,

X = (1.65 L × 44.8 L) ÷ 22.4 L

X = 3.3 L of H₂O

4 0

3 years ago

Balance the equation and determine how many liter of nitrogen are required to react with 7.3 L of hydrogen to produce ammonia (n

Musya8 [376]

Answer:

4.867 L of ammonia

Explanation:

Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :

N₂ + 3H₂ → 2NH₃

Here, 3 moles of hydrogen gas gives 2 moles of ammonia.

1 mole of any substance occupies 22.4L at STP

So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia

Then 7.3 L of hydrogen will give:

= $\frac{7.3 \times 2 \times22.4 }{3 \times22.4}$

= $\frac{7.3 \times 2}{3}$

= 4.867 L of ammonia

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3 years ago

Name the following ketone:<br> B. 3-hexanone<br> A. 2-heptanone<br> O

djverab [1.8K]

Answer:

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2 years ago