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Flura [38]
3 years ago
16

What is the power produced by a light bulb with a voltage of 120 volts and a current of 0.045 amps? PLEASE HELP I HAVE 5 MINUTES

Chemistry
2 answers:
Artyom0805 [142]3 years ago
8 0
The answer is 5.4! I found it on a an online calculator! 
GuDViN [60]3 years ago
7 0

Answer : The power produced by light bulb is, 5.4 watts

Solution : Given,

Voltage = 120 V

Current = 0.045 A

Formula used :

P=V\times I

where,

P = power produced by light bulb

V = voltage

I = current

Now put all the given values in the above formula, we get the power produced by the light bulb.

P=(120V)\times (0.045A)=5.4watts

Therefore, the power produced by light bulb is, 5.4 watts

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A sodium hydroxide solution is made by mixing 8.70 g NaOH with 100 g of water. The resulting solution has a density of 1.087 g/m
Ahat [919]

Answer:

Mass fraction = 0.08004

Mole fraction = 0.0377

Explanation:

Given, Mass of NaOH = 8.70 g

Mass of solution = 8.70 + 100 g = 108.70 g

Mass\ fraction\ of\ NaOH=\frac {8.70}{108.70} = 0.08004

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{8.70\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 0.2175\ mol

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Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{100\ g}{18.0153\ g/mol}

Moles\ of\ water= 5.5508\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ NaOH=\frac {n_{NaOH}}{n_{NaOH}+n_{water}}

Mole\ fraction\ of\ NaOH=\frac {0.2175}{0.2175+5.5508}=0.0377

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