Question

An aqueous solution of licl is 34.0 % licl. what mass of water is present in 250.0 g of the solution? (density of water is 1.00 g/ml) (solution contains only licl and water.)

Answer 1

If the aqueous solution is 34% Licl then it is 100 - 34% water = 66% From the calculation we've found out that it is 66% water. Then we need to find the weight from a 250 g solution. 66/100 * 250 = 165g Hence it is 165g

Answer 2

Answer: Mass of water present in 250 g of solution is 165 g

Explanation:

A solution contains solute and solvent. A solute is defined as the substance which is present in smaller proportion and solvent is defined as the substance which is present in larger proportion.

We are given:

34 % (m/m) of LiCl

This means that 34 g of LiCl is present in 100 g of solution.

Mass of water in solution = 100 - 34 = 66 g

We need to find the mass of water present in 250 g of solution. By applying unitary method, we get:

In 100 g of solution, mass of water present in 66 g

So, in 250 g of solution, mass of water present will be = $\frac{66}{100}\times 250=165g$

Hence, mass of water present in 250 g of solution is 165 g