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Kay [80]
3 years ago
10

In the cells of the human body,oxygen molecules are used directly in a process that

Chemistry
1 answer:
a_sh-v [17]3 years ago
6 0
<span>In the cells of the human body,oxygen molecules are used directly in a process that releases energy</span>
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A metal cube has a mass of 20 g and a volume of 5 ml. What is the density? Is the cube made of pure aluminum? Explain your answe
Shtirlitz [24]

Explanation:

Given that,

Mass of metal cube, m = 20 g

Volume of cube, V =5 mL

We need to find the density of the cube. Mass per unit volume equals density.

d=\dfrac{m}{V}\\\\d=\dfrac{20\ g}{5\ mL}\\\\d=4\ g/mL

So, the density of the cube is 4 g/ml.

We know that the density of Aluminium is 4 g/mL.

So, the cube is not Aluminium cube.

3 0
4 years ago
In what ways can geographic position be considered a temperature control?
Lesechka [4]

Near water, change in elevation, or change in latitude.

4 0
3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
Copper can be also be made by reacting copper oxide with methane
Vsevolod [243]

Answer:

a

Explanation:

3 0
2 years ago
Can anyone help with these ?
andriy [413]
Uh no I can’t help but, I hope you have a good day!
5 0
3 years ago
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