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Ymorist [56]
3 years ago
5

A quality control officer is randomly checking the weights of pumpkin seed bags being filled by an automatic filling machine. Ea

ch bag is advertised as weighing 400 grams. A bag must weigh within 2.1 grams in order to be accepted. What is the range of rejected bags, x, for the bags of pumpkin seeds?
Mathematics
2 answers:
grandymaker [24]3 years ago
8 0
If a bag of pumpkin seeds must weigh within 2.1 grams in order to be accepted, each bags must weigh between (400-2.1) grams and (400+2.1) grams. This means that if a bag weighs less than 397.9 grams (x<397.9) or more than 402.1 grams (x>402.1) it will be rejected. Therefore, 397.9>x>402.1 is the range of rejected bags.
Marianna [84]3 years ago
5 0

Answer:

x397.9 \ grams

Step-by-step explanation:

The range of rejected bags is found by summing and subtracting the 400 grams to 2.1 grams, because the second one represent the acceptable margin.

So, we have:

(400-2.1) \ grams

However, this interval represents the accepted range. The rejected range would be the opposite. Therefore, the asked range is:

x397.9 \ grams

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Answer:

The smallest power of 10 that will exceed M is 10^{6}.

Step-by-step explanation:

We can use the following approach to determine the smallest power of 10 that will exceed M. We can transform that number into scientific notation, which is of the form:

x.y \times 10^{n}, \forall \,x,y\in \mathbb{N}

Where:

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If M = 118,526.65902, then, the power grade is number of spaces that dot must be moved leftwards. In this case, dot must be moved 5 spaces on the left. The integer part is 1 and the decimal part is 1852665902. Then, the value of M in scientific notation is:

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