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lubasha [3.4K]
2 years ago
9

If an aqueous solution has a slippery feel, which type of solution will it most likely be

Physics
1 answer:
kap26 [50]2 years ago
7 0
The aqueous solution will most likely be a base.
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Electromagnetic waves require a medium to transfer energy<br> True or False
Simora [160]

The statemengt is <em>false</em>. Electromgnetic waves do not require a medium to transfer energy. They can transfer energy through vacuum (empty space with nothing in it). If electrimagnetic waves needed a medium to move through from place to place, then we could never see the sun, and also it would get very cold here.

7 0
3 years ago
What is stopping distance of a body at 20 m/s is decelerated at 2m/s² to rest?<br>​
AlladinOne [14]

Answer:

s = 100 m

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 20²) / 2(-2)

s = 100 m

5 0
2 years ago
A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
DerKrebs [107]

Answer:

A) 26.5 m/s

B) 33.0 m/s

Explanation:

A)

  • Once the car leaves the cliff, as no other influence than gravity acts on it, and since it causes the car an acceleration in the vertical direction only, in the horizontal direction, it keeps moving at the same speed until it reaches to the other side.
  • So, we can apply the definition of average velocity to find this speed as follows:

       v_{x} = \frac{\Delta x}{\Delta t}  (1)

  • We know the value of Δx, which is just the wide of the river (53.0m), but we need to find also the value of Δt.
  • This time is given by the vertical movement, whic.h is independent from the horizontal one, because both movements are perpendicular each other.
  • Since the only influence in the vertical direction is due to gravity, the car is accelerated by gravity, with constant acceleration downward equal to g = -9.8m/s² (taking the upward direction as positive).
  • Since the acceleration is constant, we can use the following kinematic equation, as follows:

       \Delta y  = y_{f} - y_{o} = v_{o} * t + \frac{1}{2}  * g *t^{2}  (2)

  • if we take the river level as our x-axis, this means that yf = 1.3 m and

       y₀ = 20.8 m.

  • At the same time, due to in the vertical direction the car has no initial velocity, this means that  v₀ = 0.
  • Replacing by the values in (2) , and solving for t:

       t = \sqrt{\frac{2* \Delta y}{g} } = \sqrt{\frac{2*19.5m}{9.8m/s2} }  = 2 s  (3)

  • If we choose t₀ =0 ⇒ Δt = t = 2 s
  • Replacing Δx and Δt in (1):

       v_{x} = \frac{\Delta x}{\Delta t} = \frac{53.0m}{2s} = 26.5 m/s  (4)

B)

  • When the car is just landing in the other side, the velocity of the car has two components, the horizontal one that we just found in A) and a vertical one.
  • Due to the initial velocity in the vertical direction was just zero, we can find the final velocity just applying the definition of acceleration, with a =g, as follows:

      v_{fy} = g*t = -9.8m/s2*2 s = -19.6 m/s  (5)

  • Since both components are perpendicular each other, we can find the magnitude of the velocity vector (the speed) using the Pythagorean Theorem, as follows:

       v = \sqrt{v_{x}^{2} + v_{fy}^{2} } } = \sqrt{(26.5m/s)^{2} + (-19.6m/s)^{2}}  = 33.0 m/s  (6)

5 0
3 years ago
Pls pls pls pls help!!!!!
Natasha2012 [34]

Answer:

The net upward force the man experiences is approximately 1,324.8 N

The net downward force the man experienced is approximately 556.8 N

Explanation:

The given mass of the man, m = 96 kg

The acceleration of the elevator, a = 4.0 m/s²

According to Newton's third law of motion which states that action ad reaction are equal and opposite, when the elevator moves upwards, we have;

The net force the man experiences, F = Gravitational force, m·g + The force of the elevator pushing upwards, m·a

∴ ↑F = m·g + m·a

Where;

F = The net force the man experiences

m = The mass of the man = 96 kg

g = The acceleration due to gravity ≈ 9.8 m/s²

a = The acceleration of the elevator = 4 m/s²

∴ ↑F = 96 kg × 9.8 m/s² + 96 kg × 4 m/s² ≈ 1,324.8 N

The net upward force the man experiences ≈ 1,324.8 N

When the elevator moves downwards, we have;

The net force the man experiences, F = Gravitational force, m·g + The loss of the gravitational force as the floor moves further downwards, -(m·a)

∴ F = m·g + -(m·a) = m·g - m·a

F = m·g - m·a

∴ ↓F = 96 kg × 9.8 m/s² - 96 k × 4 m/s² ≈ 556.8 N

The net downward force the man experienced ≈ 556.8 N

8 0
2 years ago
What will be the change in velocity of a 850 kg car if a force of 50,000N is
Gala2k [10]

Answer:

i'm not quite sure

Explanation:

just grive me a sec

4 0
3 years ago
Read 2 more answers
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