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AlekseyPX
2 years ago
7

If a substance was described as smooth, square, and tan, what properties are

Physics
2 answers:
Nastasia [14]2 years ago
8 0
D.) is the correct answer!
Sergeeva-Olga [200]2 years ago
4 0

D. Physical properties

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A plane has a takeoff speed of 89.3m/s and requires 1465m to reach that speed determine the acceleration of the plane and the ti
Tems11 [23]

Answer:

a = 2.72 ms⁻²

32.83 s

Explanation:

By using the kinematic equations you get,

v² = u² +2as and v = u + at   where all terms in usual meaning

Using 1st equation,

89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²

By 2nd equation,

89.3 = 0 + 2.72×t ⇒ t = 32.83 s

4 0
3 years ago
In order to ride a bike up a hill with increasing speed—
sergey [27]

Answer: the rider’s pedal force must be greater than friction and the force of gravity

Explanation:

This is because if the pedal force was less, you would go slower, and it is obviously not impossible to ride up a hill without increasing speed. But if the force was greater, your speed would increase.  

5 0
2 years ago
When starting a foot race, a 64 kilogram sprinter exerts an average force of 693 newtons backward on the ground for 0.59 seconds
cluponka [151]

The distance traveled by the sprinter in meters is determined as 1.88 m.

<h3>Acceleration of the sprinter</h3>

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

  • F is the applied force by the sprinter
  • m is mass of the sprinter
  • a is acceleration of the sprinter

a = 693 N / 64 kg

a = 10.83 m/s²

<h3>Distance traveled by the sprinter</h3>

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

  • u is initial velocity = 0

s = ¹/₂at²

where;

  • t is time of motion
  • a is acceleration

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

6 0
1 year ago
The change in momentum that occurs when a 1. 0 kg ball traveling at 4. 0 m/s strikes a wall and bounces back at 2. 0 m/s is.
Doss [256]

Answer:

The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s

Explanation:

momentum is the product of mass and velocity (speed)

So it's initial momentum would be:

p=mv=(1)(4)=4 kg.m/s

It's final momentum is given by:

p=mv=(1)(2)=2 kg.m/s

7 0
2 years ago
A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
Reil [10]
To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
Centripetal Acceleration = v squared divided by r

where:
v = velocity, m/s
r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
                                      = 81 m/s^2

at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
                                      = 16.2 m/s^2

to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

= 81 m/s^2 - 16.2 m/s^2
= 64.8 m/s^2 or 65 m/s^2
6 0
3 years ago
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