Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3 
= 5 3 2
x_{f} = 45 m
we substitute
v = 15 m / s
Answer:
Explanation:
Given
mass (m)= 20 kg
acceleration (a)= 10 m/s^2
Force (f)= m a
= 20 * 10
= 200 N
Force equals mass time acceleration. Weight is a force and it can replace force in the equation. The acceleration would be gravity, which is an acceleration.
1.)
Fw (weight) = m (mass) · g (gravity, 9.8 m/s²)
Fw = m * 9.81 m/s²
560N = m · 9.81 m/s²
m ≈ 57.08 kg
2.)
d = 350 meters
t = 65 seconds
velocity = d/t
velocity = 350 meters / 65 seconds
velocity ≈ 5.38 meters/sec
3.)
Force = 35N
Distance = 2 meters
Work = Force · Distance
Work = 35N · 2 meters
Work = 70 J
The ratio of the speed of light v in a medium to the speed of light in a vacuum c is called its Refractive Index n
v/c=n
Different substances have different Refractive Indices (plural of Index). Values are always bigger than 1.
Refractive index of water is 1.33
Refractive index of glass is about 1.4
