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xxMikexx [17]
3 years ago
12

Suppose your class invites a person to give a speech. When you test out the sound system in the gym you find there are so many e

choes the speaker cannot be understood. What needs to be done to fix this problem?
Physics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

You either need to lower the volume so the sounds intensity is lessened. Or you can pad the walls to absorb the sound rather than defect.

Explanation:

Sound intensity allows it to be heard further, but in an enclosed room it will start returning. Sound will deflect off of hard objects do to its interactions with solids. A softer and foamy material can dampen it.

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Force F acts between a pair of charges, q1 and q2, separated by a distance d. For each of the statements, use the drop-down menu
lora16 [44]

The initial force between the two charges is given by:

F=k \frac{q_1 q_2}{d^2}

where k is the Coulomb's constant, q1 and q2 the two charges, d their separation. Let's analyze now the other situations:

1. F

In this case, q1 is halved, q2 is doubled, but the distance between the charges remains d.

So, we have:

q_1' = \frac{q_1}{2}\\q_2' = 2 q_2\\d' = d

So, the new force is:

F'=k \frac{q_1' q_2'}{d'^2}= k \frac{(\frac{q_1}{2})(2q_2)}{d^2}=k \frac{q_1 q_2}{d^2}=F

So the force has not changed.

2. F/4

In this case, q1 and q2 are unchanged. The distance between the charges is doubled to 2d.

So, we have:

q_1' = q_1\\q_2' = q_2\\d' = 2d

So, the new force is:

F'=k \frac{q_1' q_2'}{d'^2}= k \frac{q_1 q_2)}{(2d)^2}=\frac{1}{4} k \frac{q_1 q_2}{d^2}=\frac{F}{4}

So the force has decreased by a factor 4.

3. 6F

In this case, q1 is doubled and q2 is tripled. The distance between the charges remains d.

So, we have:

q_1' = 2 q_1\\q_2' = 3 q_2\\d' = d

So, the new force is:

F'=k \frac{q_1' q_2'}{d'^2}= k \frac{(2 q_1)(3 q_2)}{d^2}=6 k \frac{q_1 q_2}{d^2}=6F

So the force has increased by a factor 6.

8 0
3 years ago
Read 2 more answers
Why is heat acclimatization important?
kicyunya [14]

Answer:

Heat acclimatization :

   It is the biological adaptations or we can say that it coverts according to the present environment.It also reduce the strain and maintain the normal temperature and heart rate.Heat acclimatization also increase the comfort and reduce all the mental strain and also protect out liver ,muscles ,kidneys and brain fro the injury.

5 0
3 years ago
A truck with 0.410 m radius tires travels at 25.0 m/s. What is the angular velocity of the rotating tires in radians per second?
Eduardwww [97]

relation between linear velocity and angular velocity is given as

v = R\omega

here

v = linear speed

R = radius

\omega = angular speed

now plug in all data in the equation

25.0 = 0.410 \omega

\omega  = \frac{25}{0.410}

\omega = 60.9 rad/s

so rotating speed is 60.9 rad/s

6 0
3 years ago
When sunlight strikes the side of a building, what form of energy is it<br> transformed to?
algol [13]

Answer:

thermal energy

Explanation:

8 0
3 years ago
A 21.7kg child descends a slide 3.5 m high and reaches the bottom with a speed of 2.2m/s. How much thermal energy due to frictio
nadya68 [22]

Answer:

Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.

Potential energy loss:

M g H = 21.7*9.81*3.5 = 745.1 J

Kinetic energy at bottom of slide:

= (1/2) M v^2 = 52.5 J

5 0
3 years ago
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