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xxMikexx [17]
3 years ago
12

Suppose your class invites a person to give a speech. When you test out the sound system in the gym you find there are so many e

choes the speaker cannot be understood. What needs to be done to fix this problem?
Physics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

You either need to lower the volume so the sounds intensity is lessened. Or you can pad the walls to absorb the sound rather than defect.

Explanation:

Sound intensity allows it to be heard further, but in an enclosed room it will start returning. Sound will deflect off of hard objects do to its interactions with solids. A softer and foamy material can dampen it.

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navik [9.2K]
<span>To calculate the density, we must first calculate the volume of the object. For a rectangle, the volume is equal to V=l*w*h. In this case, V=22*13.5*12.5=3712.5 mm^3. Next we have to convert the mm^3 to mL using the conversion factor of 1 mm^3=.001 mL. To get mL, we set up the expression 3712.5 mm^3 * (.001mL/1mm^3) = 3.7125 mL. Finally, to get the density, we know density is mass over volume, so we set the expression p=m/V=2.5g/3.7125mL=.6734 which rounded to 3 significant figures is .673. The answer will be .673</span>
8 0
3 years ago
In a single-slit diffraction experiment, a coherent light source illuminates a slit in a barrier, and the resulting pattern is p
UkoKoshka [18]

Answer:

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Explanation:

4 0
3 years ago
I need the answer asap plz!!
Vesnalui [34]

Answer:

266.7k

Explanation:

Given parameters:

Initial pressure  = 36Pa

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New pressure  = 32Pa

Unknown:

New temperature  = ?

Solution:

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in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

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1 and 2 are initial and final states

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erastova [34]

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7 0
3 years ago
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