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3 years ago

How much energy is needed to warm 7.40g of water by 55 degress C?

1 answer:

8 0

<span>E = mCdT
E = energy, m = mass, C = specific heat capacity, dT = change in temperature.
526 = 0.074C x 17
E = 0.074C x 55
Divide the equations
E/526 = (0.074C x 55)/(0.074C x 17) = 55/17
E = (55 x 526)/17 = 1702 J</span>

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How much energy does cameron need to add to raise the temperature of a 0.500-kg sample of silver from 200 k to 205 k? the specif

zzz [600]

energy to raise temperature is 590 J

Given:

mass of silver sample = 0.5 kg

initial temperature = 200 k

final temperature = 205 k

specific heat of silver = 236 j/kgk

To Find:

energy to raise temperature

Solution: The heat energy required to raise the temperature of of a substance through is called its specific heat capacity.

Q = cmΔt

where c= constant of proportionality, called specific heat capacity of the body

Q = mass x specific heat x ∆t

= 0.5 x 236 x ( 205-200 )

= 590 J

So, energy to raise temperature is 590 J

Learn more about Specific heat capacity here:

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2 years ago

Suppose that a solution is tested for NO2 ion by adding 3M H2SO4 and heating, repeating this process until no further reaction o

Arada [10]

Answer:

The correct equation will be "[Fe(H2O)5]²⁺ + NO → Fe(H2O)5NO]²+ (brown ring) ".

Explanation:

For NO₂, the addition of H₂SO₄ forms HNO₂ comprising NO gas as well as HNO₂, the equation will be:

⇒ NO₂⁻ + 2H⁺ → HNO2

⇒ HNO₂ + H₂O + H⁺ → HNO₃ + NO

For NO₃⁻,

NO₃⁻, Fe₂+ oxidized to Fe₃ + then releases NO gas in the existence of H₂SO₄

⇒ 3Fe₂⁺ + 4H⁺ + NO₃⁻ → 3Fe₃⁺ + NO + 2H₂O

Brown ring forming establishes NO3- presence in the initial test sample,

⇒ [Fe(H2O)5]²⁺ + NO → Fe(H2O)5NO]²+ (brown ring)

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3 years ago

A 5.5 gg sample of a substance contains only carbon and oxygen. Carbon makes up 35%% of the mass of the substance. The rest is m

Elan Coil [88]

Answer:

a. ((100 - 35)/100) times 5.5 grams = 3.575 g

Explanation:

Given that:

The sample of carbon and oxygen = 5.5g

where carbon makes 35% of the mass of the substances.

It implies that oxygen will make: (100 - 35)% = 65%

Suppose y be the mass of the oxygen;

Then:

$y = \dfrac{(100-35)}{100} \times 5.5 \ g$

$y = \dfrac{(65)} {100} \times 5.5 \ g$

$y = 3.575 \ g$

The mass of carbon $= \dfrac{35}{100} \times 5.5 \ g$

= 1.925 g

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3 years ago

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Answer:

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3 years ago

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Andre45 [30]

It is a solution where a solute cannot dissolve anymore into the solvent.

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