3 years ago

How much energy is needed to warm 7.40g of water by 55 degress C?

1 answer:

8 0

<span>E = mCdT
E = energy, m = mass, C = specific heat capacity, dT = change in temperature.
526 = 0.074C x 17
E = 0.074C x 55
Divide the equations
E/526 = (0.074C x 55)/(0.074C x 17) = 55/17
E = (55 x 526)/17 = 1702 J</span>

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Answer:

The answer to your question is 0.269 g of Pb

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