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strojnjashka [21]
3 years ago
14

Is a substance that a filter can seperate into two parts a mixture or a pure substance?

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
7 0
Mixture. Mixtures can be separated into their component parts, while substances are chemically bonded atoms that can't be separated by physical means.
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According the VSEPR theory the molecular geometry for CH3+ is triagonal planar
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__HgO __Hg + __O2 what is the reaction
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2HgO <---- 2Hg + O2

Explanation:

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Now since i helped you can you help me with this plz

Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.

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Which factors help you identify the solute and the solvent in a solution? Select all that apply. In a solution, the solvent is p
KatRina [158]

The answers would be:

In a solution, the solvent is present in a greater amount.

In a solutions, the solute dissolves in a solvent.

In general, these are the best answers. The solute is what is being dissolved and the solvent is what dissolves. A solvent comes in greater amounts in a solution and it is the dissolving agent.

For example, sugar and water.

To make a sugar water solution, you will need to dissolve sugar in water. Sugar is the solute in this case because it is what is being dissolved. The water is the solvent, because it dissolves the sugar.

If you had more sugar than water, then you cannot make a solution.  

4 0
3 years ago
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A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
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