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nata0808 [166]
3 years ago
5

2.00 moles of CO2 and 1.50 moles of H2 are placed into a rigid 5.00-L container and they react according to the equation CO2(g)

+ H2(g) ⇄ CO(g) + H2O(g) K = 2.50 What will be the concentration of carbon monoxide when equilibrium is reached? 0.191 M 0.091 M 0.209 M (Your correct answer) 0.913 M 1.05 M
Chemistry
1 answer:
shtirl [24]3 years ago
3 0

Answer: 0.209 M

Explanation:

Moles of  CO_2 = 2.00 mole

Moles of  H_2 = 1.50 mole

Volume of container = 5.00 L

Initial concentration of CO_2 = \frac{moles}{Volume}=\frac{2.00mol}{5.00L}=0.400M

Initial concentration of H_2 = \frac{moles}{Volume}=\frac{1.50mol}{5.00L}=0.300M

The given balanced equilibrium reaction is,

                         CO_2(g)+H_2(g)\rightleftharpoons CO(g)+H_2O(g))

Initial conc.          0.400 M          0.300M             0 M        0 M

   At eqm. conc.     (0.400-x) M   (0.300-x) M   (x) M      (x)  M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [H_2O]}{[H_2]\times [CO_2]}

Now put all the given values in this expression, we get :

2.50=\frac{[x]\times [x]}{[0.300-x]\times [0.400-x]}

By solving the term 'x', we get :

x = 0.209 M

Concentration of CO at equilibrium = x M  =  0.209 M

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taurus [48]
The answer is C as enzymes are biological catalysts that act on a substrate such as starch if the enzyme were amylase

hope that helps 
5 0
3 years ago
Read 2 more answers
0.05 grams od cobalt ii oxalate will dissolve in one liter of solution at 25 degree celcius. Calculate the ksp for cobalt ii oxa
Veseljchak [2.6K]

Answer:

The equilibrium expression is:

CoC2O4(s)⇌Co2+(aq)+C2O2−4(aq)

For this reaction:

Ksp = [Co2+][C2O2−4]=1.96×10−8

Explanation:

Batteries will not clot if cobalt ions are removed from its cells. Some blood collection tubes contain salts of the oxalate ion,

C2O2−4

, for this purpose. At sufficiently high concentrations, the calcium

and oxalate ions form solid, CoC2O4·H2O (which also contains water bound in the solid). The concentration of Co2+ in a sample of blood serum is 2.2 × 10–3M. What concentration of

C2O2−4

ion must be established before CoC2O4·H2O begins to precipitate.

CoC2O4 does not appear in this expression because it is a solid. Water does not appear because it is the solvent.

Solid CoC2O4 does not begin to form until Q equals Ksp. Because we know Ksp and [Co2+], we can solve for the concentration of

C2O2−4

that is necessary to produce the first trace of solid:

5 0
3 years ago
The freezing temperatures for water for Celsius and Fahrenheit scales are 0ºC and 32ºF. The boiling temperatures for water are 1
ddd [48]

Answer:

Therefore the required function is

C= \frac{5}{9} (F-32)

Therefore 25°C=57°F

Explanation:

F denotes temperature of Fahrenheit and C denotes temperature of Celsius.

\frac{C-0}{100-0} =\frac{F-32}{212-32}

\Rightarrow C= \frac{100}{180} (F-32)

\Rightarrow C= \frac{5}{9} (F-32)

Therefore the required function is

C= \frac{5}{9} (F-32)

Putting C=25°C in above equation

25=\frac{5}{9} (F-32)

\Rightarrow 25 \times \frac{9}{5} = F-32

⇒45 =F-32

⇒F=32+45

⇒F=57

Therefore 25°C=57°F

7 0
3 years ago
Given that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer,
marishachu [46]

Answer:

0.013%

Yes, it does. The answer agrees with the statement.

Explanation:

Both conformers are in equilibrium, and it can be represented by the equilibrium equation K:

K = [twist-boat]/[chair]

The free energy between them can be calculated by:

ΔG° = -RTlnK

Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C + 273 = 298 K).

ΔG° = 5.3 kcal/mol * 4.182 kJ/kcal = 22.165 kJ/mol = 22165 J/mol

22165 = -8.314*298*lnK

-2477.572lnK = 22165

lnK = -8.946

K = e^{-8.946}

K = 1.30x10⁻⁴

[twist-boat]/[chair] = 1.30x10⁻⁴

[twist-boat] = 1.30x10⁻⁴[chair]

The percentage of the twist-boat conformer is:

[twist-boat]/([twist-boat] + [chair]) * 100%

1.30x10⁻⁴[chair]/(1.30x10⁻⁴[chair] + [chair]) *100%

0.013%

The statement about the conformers is that the chair conformer is more stable, and because of that is more present. So, the answer agrees with it.

3 0
3 years ago
4) Ethanol has a density of 0.8 g/cm3. <br> What is the mass of 225 cm3 of ethanol
AveGali [126]

Answer:

\huge\boxed{\sf m = 180\  g}

Explanation:

<u>Given:</u>

Density = ρ = 0.8 g/cm³

Volume = V = 225 cm³

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

m = ρV

<u>Solution:</u>

m = (0.8)(225)

m = 180 g

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
2 years ago
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