<u>Answer: </u>The molar mass of the metal is 96.45 g/mol
<u>Explanation:</u>
The fluoride of the metal formed is 
The oxidation half-reaction follows:

Calculating the theoretical mass deposited by using Faraday's law, which is:
......(1)
where,
m = actual mass deposited = 1.25 g
M = molar mass of metal = ?
I = average current = 3.86 A
t = time period in seconds = 16.2 min = 972 s (Conversion factor: 1 min = 60 sec)
n = number of electrons exchanged = 
F = Faraday's constant = 96500 C
Putting values in equation 1, we get:

Hence, the molar mass of the metal is 96.45 g/mol