Question

A manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope What inequality Could it is to find the possible width, w, of the rope-off section

Answer 1

Answer:

$15.2+2w\leq 28$

Step-by-step explanation:

Let w represent width of the rope-off section.

We have been given that a manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope.

We will use perimeter of rectangle formula to solve our given problem. We know that perimeter of a rectangle is equal to 2 times the sum of length and width.

$\text{Perimeter}=2l+2w$

Upon substituting our given values, we will get:

$\text{Perimeter}=2(7.6)+2w\\\\\text{Perimeter}=15.2+2w$

Since the manager can use no more than 28 m of the rope, so perimeter of rope-off section should be less than or equal to 28 meters.

We can represent this information in an inequality as:

$15.2+2w\leq 28$

Therefore, our required inequality would be $15.2+2w\leq 28$.

Let us find width as:

$15.2-15.2+2w\leq 28-15.2$

$2w\leq 12.8$

$\frac{2w}{2}\leq \frac{12.8}{2}\\\\w\leq6.4$

Therefore, the width of the rope-off section should be less than or equal to 6.4 meters.