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likoan [24]
3 years ago
14

Please help ASAP.

Chemistry
1 answer:
Lady_Fox [76]3 years ago
8 0
Looked it up for you. Hope this helps

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I need help with B and C
lakkis [162]
B) Mg is the alkaline earth metal w/12 protons so following the periodic table to the halogen in the same period is

Cl: Chlorine

C) The Neutral noble has w/ 18 electrons is argon so the metal in the same row is

Na: Sodium
8 0
3 years ago
How many moles are in 4561 g of C3H7OH?
d1i1m1o1n [39]

Answer: 76.017 moles

Explanation:

3 0
2 years ago
When the equation Al2(SO4)3 + NaOH + Al(OH)3 + Na2SO4 is correctly balanced, what is the coefficient of Al(OH)3?
nevsk [136]
The balanced chemical formula should be Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4

Therefore the coefficient of Al(OH)3 is 2!

Hope that helps :)
4 0
3 years ago
A relationship in which one variable increases as the other variable decreases is an inverse relationship.
Brut [27]

Answer:

TRUE

Explanation:

HOPE IT WILL HELP YOU

8 0
3 years ago
Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9
galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = \frac{V_{2}}{3M_{1}V_{1}}=0.928M

3 0
3 years ago
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