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STALIN [3.7K]
3 years ago
5

How many moles of copper are equivalent to 3.44x10^23 atoms of copper?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

0.571moles

Explanation:

The Avogrado's number or constant denoted by NA will be used for this question.

The Avogrado's number = 6.022 × 10^23 particles, is contained in 1 mole of a substance.

To get the number of atom/particles in a substance, the formula: N= n × NA is used.

Where; N= Number of atoms in

substance

n= number of moles

NA= Avogadro's constant

Hence, to find the number of moles of copper equivalent to 3.44 × 10^23, we say: n= N / NA

That is, n = 3.44 × 10^23 / 6.022 × 10^23

= 0.5712

Therefore, 0.571 moles of Copper (Cu) is equivalent to 3.44 × 10^23 atoms of Copper.

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<h3>What is Molecular Formula ?</h3>

The chemical formula that gives total number of atoms of each element in one molecule of a compound is called Molecular Formula.

<h3>What is Oxidation State ?</h3>

Oxidation state is also known as oxidation number. It is defined as the atom is equal to the total number of electrons which have been removed from the element in order to form chemical bond with other atom.

Now find the oxidation state of Pb in Pb(C₂H₃O₂)₂ .3H₂O

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x = 2

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Thus from the above conclusion we can say that The systematic name for the formula Pb(C₂H₃O₂)₂ .3H₂O is Lead (II) acetate trihydrate.

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Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce
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The answer is "10.84 g".

Explanation:

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\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }

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Owing to the nitric acid mass = 75.9 g

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If they put values above the formula, they receive:

\text{moles in nitric acid} = \frac{75.9}{63}

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3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.

So, 1.204 moles of nitric acid will be produced:

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Water moles = 0.602\  mol

Water weight molar = 18.02 \ \frac{g}{mol}

\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\

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