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STALIN [3.7K]
3 years ago
5

How many moles of copper are equivalent to 3.44x10^23 atoms of copper?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

0.571moles

Explanation:

The Avogrado's number or constant denoted by NA will be used for this question.

The Avogrado's number = 6.022 × 10^23 particles, is contained in 1 mole of a substance.

To get the number of atom/particles in a substance, the formula: N= n × NA is used.

Where; N= Number of atoms in

substance

n= number of moles

NA= Avogadro's constant

Hence, to find the number of moles of copper equivalent to 3.44 × 10^23, we say: n= N / NA

That is, n = 3.44 × 10^23 / 6.022 × 10^23

= 0.5712

Therefore, 0.571 moles of Copper (Cu) is equivalent to 3.44 × 10^23 atoms of Copper.

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Explanation:

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\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

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(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}

(5.50-T_f)^0C=6.68

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Thus the freezing point of a solution will be -1.16^0C

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