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STALIN [3.7K]
3 years ago
5

How many moles of copper are equivalent to 3.44x10^23 atoms of copper?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

0.571moles

Explanation:

The Avogrado's number or constant denoted by NA will be used for this question.

The Avogrado's number = 6.022 × 10^23 particles, is contained in 1 mole of a substance.

To get the number of atom/particles in a substance, the formula: N= n × NA is used.

Where; N= Number of atoms in

substance

n= number of moles

NA= Avogadro's constant

Hence, to find the number of moles of copper equivalent to 3.44 × 10^23, we say: n= N / NA

That is, n = 3.44 × 10^23 / 6.022 × 10^23

= 0.5712

Therefore, 0.571 moles of Copper (Cu) is equivalent to 3.44 × 10^23 atoms of Copper.

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7 0
3 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
*GIVING BRAINLIEST* NEED ANSWER ASAPPP
poizon [28]

Same Question here answered by me with explanation check the link below for your answer.

brainly.com/question/24944271?

8 0
3 years ago
1.
Makovka662 [10]

Answer:

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OLga [1]

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3 0
3 years ago
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