The geometry of the double bond is almost always a cis configuration in natural fatty acids<span>. These molecules </span>do<span> not "stack" very well. The intermolecular interactions are much weaker than </span>saturated <span>molecules. As a result, the melting </span>points<span> are much </span>lower<span> for </span>unsaturated fatty acids<span>.
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Answer:
2.9 grams.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:
no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.
no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.
<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>
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<em><u>Using cross multiplication:</u></em>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.074 mol of Mg produce → 0.074 mol of MgO.
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>
They are all <u>non-metal elements</u>.
Answer:
- Absolute zero is - 459.67 °F
Explanation:
<u>1) Convert absolute zero to celsius:</u>
- 0 K = - 273.15°C ( this is per definition of the scale)
<u>2) Convert - 273.15°C to Fahrenheit:</u>
- T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=
- T (°F) = - 273.15 × 1.8 + 32 = - 459.67 °F ← answer
Since Lutetium-177 is a beta and gamma emitter, the daughter nuclide produced from the decay of this radioisotope is 177Hf.
Beta emission of a radioisotope yields a daughter nuclide whose amass number is the same as that of its parent nucleus but its atomic number is greater is greater than that of the parent nucleus by 1 unit.
Also, gamma emission does not lead to any change in the mass number of atomic number of the daughter nucleus produced.
Hence, the stable daughter nuclide, 177Hf is produced.
Learn more: brainly.com/question/1770619