Solution :
1. Rayleigh scattering takes place when the particle size is smaller than the wavelength (λ).
2. Mie scattering takes place when particle size is nearly equal to the wavelength (λ).
3. Non-selective scatter takes place when particle size in greater than the wavelength (λ).
We have the sizes of different particles :
![$O_2 \rightarrow 10^{10} \ m $](https://tex.z-dn.net/?f=%24O_2%20%5Crightarrow%2010%5E%7B10%7D%20%5C%20m%20%24)
Smoke particles ![$\rightarrow 3 \times 10^{-7} \ m$](https://tex.z-dn.net/?f=%24%5Crightarrow%203%20%5Ctimes%2010%5E%7B-7%7D%20%5C%20m%24)
Cloud droplets ![$\rightarrow 2 \times 10^{-5} \ m$](https://tex.z-dn.net/?f=%24%5Crightarrow%202%20%5Ctimes%2010%5E%7B-5%7D%20%5C%20m%24)
Rain droplets ![$\rightarrow 3 \times 10^{-3} \ m$](https://tex.z-dn.net/?f=%24%5Crightarrow%203%20%5Ctimes%2010%5E%7B-3%7D%20%5C%20m%24)
Wavelength
Smoke particles Cloud droplets Rain droplets
![$ 3 \times 10^{-3} \ m$](https://tex.z-dn.net/?f=%24%203%20%5Ctimes%2010%5E%7B-3%7D%20%5C%20m%24)
Rayleigh Non-selective Non-selective Non-selective
Rayleigh Rayleigh Non-selective Non-selective
Rayleigh Non-selective Non-selective Non-selective
Rayleigh Rayleigh Rayleigh Mie
False because nucleus just consists proton which is positively charged and neutron which is neutral. It does not contain electron , so nucleus only can be positive charge
This is kind of an awkward situation.
A, B, and C are definitely false:
A ... gasoline is not a renewable resource
B ... hydroelectric dams don't use wind for anything; windmills do
C ... fossil fuels are not renewable resources
So that leaves D, but D is partly absurd too.
Natural gas burning does not produce gases to turn the turbines. Natural gas is burned to produce HEAT, just like on the stove in my kitchen. The heat is used to boil water, and the steam from the boiling water is what turns the turbines to generate electrical energy.
But I guess you gotta pick <em>choice-D</em> as the answer.
Answer: AHH PROBABLY THE FIRST OPTION
Answer:
F=480.491 N
Explanation:
Given that
mass ,m = 22 kg
Angular speed ω = 40 rev/min
![\omega=\dfrac{2\pi \times 40}{60}\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B2%5Cpi%20%5Ctimes%2040%7D%7B60%7D%5C%20rad%2Fs)
ω =4.18 rad/s
The radius r= 1.25 m
We know that centripetal force is given as
F=m ω² r
Now by putting the values in the above equation we get
![F=22\times 4.18^2\times 1.25\ N](https://tex.z-dn.net/?f=F%3D22%5Ctimes%204.18%5E2%5Ctimes%201.25%5C%20N)
F=480.491 N
Therefore the centripetal force on the child will be 480.491 N.