Answer:
Trial 1: 2 Volts, 0 %
Trial 2: 2.8 Volts, 0%
Trial 3: 4 Volts, 0 %
Explanation:
Th experimental values are given in the table, while the theoretical value can be found by using Ohm/s Law:
V = IR
<u>TRIAL 1</u>:
V = IR
V = (0.1 A)(20 Ω)
<u>V = 2 volts</u>
% Difference =
x 100%
% Difference = |(2 - 2)/2| x 100%
<u>% Difference = 0 %</u>
<u>TRIAL 2</u>:
V = IR
V = (0.14 A)(20 Ω)
<u>V = 2.8 volts</u>
% Difference =
x 100%
% Difference = |(2.8 - 2.8)/2.8| x 100%
<u>% Difference = 0 %</u>
<u></u>
<u>TRIAL 3</u>:
V = IR
V = (0.2 A)(20 Ω)
<u>V = 4 volts</u>
% Difference =
x 100%
% Difference = |(4 - 4)/4| x 100%
<u>% Difference = 0 %</u>
Answer:

Explanation:
From the question we are told that:
Separation Distance 
Potential difference 
Generally the equation for Electric Field strength is mathematically given by



The troposphere is the lowermost layer of the Earth's atmosphere. Most of the weather phenomena, systems, convection, turbulence and clouds occur in this layer, although some may extend into the lower portion of the stratosphere.