Answer:
<em>61.9°</em>
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
<em>Hence the angle that the rope makes with the horizontal is 61.9°</em>
Answer:
I think this is something you're looking for so I hope they help
Explanation:
The question is incomplete, these are the missing parts of the question.
b) What is the baseball's acceleration in g's? (Indicate the direction with the sign of your answer.)
(b) What is the size of the force acting on it?
Answer:
a) -14333.3ms-2
b) -1462.58g
c) 2078N
Explanation:
The acceleration (deceleration) is easily found from from the information provided. Then the acceleration is obtained in terms of g as shown in the solution attached. The force is obtained from F=ma as shown in the image attached. Note the acceleration is negative because the ball was coming to rest. (The ball was caught).
Answer:
W = 907963.50 J = 907.96 J
Explanation:
Note: Refer to the figure attached
Now, from the figure we have similar triangles ΔAOB and ΔCOD
we have

or

Now, the work done to empty the tank can be given as:

or

or

or

or
![W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B5%7D%7B3%7Dx%5E3-%5Cfrac%7B1%7D%7B4%7Dx%5E4%5D%5E4_0%20)
or
![W = 6773.76\pi[\frac{128}{3}]](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B128%7D%7B3%7D%5D%20)
or
W = 907963.50 J = 907.96 J
Answer:
150 N= 15 or 150 N= 1.1
Explanation:
What I did was subtract 165kg and 150 N and I divided it too but I got 1.1 so yuhh