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swat32
4 years ago
14

An amplifier has an input power of 5 mW. The output power is 100 mW. What is the decibel gain to the nearest decibel?

Physics
1 answer:
ZanzabumX [31]4 years ago
3 0

Answer:

<em>The decibel gain to the nearest decibel = 13 db </em>

Explanation:

Gain of an amplifier: This is defined as the measure of the ability of an amplifier to increase the power of a signal from the input to the output port by adding energy converted from some power supply to the signal.

It is represented mathematically as.

db = 10×log (p₂/p₁)............................. Equation 1

Where dp = decibel gain of the amplifier, p₁ = input power of the amplifier, p₂ = output power of the amplifier.

<em>Given: p₁ = 5 mW, p₂ = 100 mW.</em>

<em>Substituting these values into equation 1</em>

db = 10×log(100/5)

db = 10×log(20)

dp = 10 ×1.301

<em>dp = 13 db gain</em>

<em>Therefore the decibel gain to the nearest decibel = 13 db </em>

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