Answer:
Explanation:
Volume of a cone:
We have 
and we want to find 
when the height is 2 cm.
We can see in our equation for the volume of a cone that we have three variables: V, r, and h.
Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.
We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.
Plug this value for r into the volume formula:
Differentiate this equation with respect to time t.
Plug known values into the equation and solve for dh/dt.
Divide both sides by 100π to solve for dh/dt.
The height of the cone is increasing at a rate of 1/10π cm per second.
Answer:
The answer to your question is all the formulas in bold has the same empirical formula
Explanation:
Data
Empirical formula CH₂O
Process
To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.
a) C₂H₄O₂ factor 2 2(CH₂O)
b) C₃H₆O₃ factor 3 3(CH₂O)
c) CH₂O₂ this formula can not be simplified
d) C₅H₁₀O₅ factor 5 5(CH₂O)
e) C₆H₁₂O₆ factor 6 6(CH₂O)
Answer:
<em>It is false.</em>
Explanation:
<em>Weathering is the general process by which rocks are broken down at Earth's surface. Erosion is a set of processes that loosen and move soil and rock downhill or downwind. Umm...for example, imagine you are having ice cream in your hand out on a sunny day, if the ice-cream melts and falls down, it is called erosion and if the ice-cream melts but it doesn't fall down, it called weathering. </em>
Answer:
Q = 25360.269 j
Explanation:
Given data:
Mass = 165 g
Initial temperature = 10.55 °C
Final temperature = 47.32°C
Energy absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 47.32°C - 10.55 °C
ΔT = 36.77 °C
Q = m.c. ΔT
Q = 165 g . 4.18 j/g.°C . 36.77 °C
Q = 25360.269 j
