When the coffee is brewed according to directions, a pound of coffee beans yields 50 cups of coffee (4 cups = 1 qt). How many kg
1 answer:
You might be interested in
The compound is formed only by sharing of electrons between the atoms. The structure of the compound is shown in the image.
Each line between two atoms represents the sharing of an electron pair which results in the formation of a single bond. Since, carbon has 4 electrons in its valence shell and hydrogen has 1 electron in its valence shell so in order to complete the octet ( to have 8 electrons in their valence shell, noble gas configuration) to attain stability carbon needs 4 more electrons and hydrogen needs 1 electron. So, sharing of electron will occur as shown in the image and the formed compound is stable in nature.
Since, the bond that is formed by sharing of electrons between atoms is known as covalent bond. So, covalent bonding is most important in .
Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.
<h3>Percentage composition</h3>The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.
Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
In this case, you know:
- mass of solute= 46.63 g
- mass of solution= 75 g
Replacing:
Solving:
<u><em>percentage by mass= 62.17 %</em></u>
Finally, the percent composition of carbon in this sample is 62.17%.
Learn more about percent composition:
<u>brainly.com/question/24201923?referrer=searchResults</u>