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Sindrei [870]
3 years ago
8

Read the Casestudy Conservation Planning and summarize it - 5 sentence minimum.

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

Developing Conservation Case Studies for Decision-making ... titled “Producer Experiences” or “Case Studies” for use in future planning efforts and ... convince a producer of the benefits of conservation, or at least help them understand the ... Easy to read, especially for those that are not comfortable with economics or data​.

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How many ug of nickel (Ni) are required to make 25.00 nanoliters of a 1.25 mol/L solution? Be sure to report your answer to the
devlian [24]

volume of Ni = 25 nL = 25 x 10⁻⁹ L

mol Ni = 25 x 10⁻⁹ L x 1.25 mol/L = 3.125 x 10⁻⁸

mass = mol x Ar Ni

mass = 3.125 x 10⁻⁸ x 59 g/mol

mass = 1.84 x 10⁻⁶ g = 1.84 μg

4 0
2 years ago
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Consider these elements: p, ca, si, s, ga.<br> a. write the electron configuration for each element
dimulka [17.4K]
Method:

1) Find the atomic number in a periodic table: the number of electrons equal the atomic number

2) Use Aufbau rule

Element     atomic number       electron configuration
<span>
P                15                            1s2 2s2 2p6 3s2 3p3

Ca              20                            </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2

</span>Si                14</span><span>                            1s2 2s2 2p6 3s2 3p2

S                 16</span><span><span>                            1s2 2s2 2p6 3s2 3p4

</span>Ga               31.                   </span><span><span>        1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span>       </span>
7 0
4 years ago
Calculate the pH of a 2.0 M H2SO4 solution.
noname [10]
 <span>H2SO4 gives 2 moles oh H+ per mole of acid 

[H2SO4] = 2M so [H+] = 4M 

pH = -log(4) = -.6 

Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
4 years ago
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Metabolic activity in the human body releases approximately 1.0 x 104kJ of heat per day. Assuming the body is 50 kg of water, ho
Zarrin [17]

Answer:

The body temperature would rise by 47.85 °C

The  amount of water the body evaporates is  4.15 kg.

This makes sense because firstly the value obtained is positive  then secondly it is a normal occurrence in the real world that in a place where the temperature is high the body usually produce sweat in order to balance its internal temperature

Explanation:

Considering the relationship (between the heat released and the mass of the object)  as shown below

              q = msΔT    

where q is the heat released per day = 1.0 * 10^{4} kJ

              m is the mass of the body  = 50 kg

              ΔT  is the temperature rise = ?

               s is the specific heat  of water =  4,18kJ/kg^{o} C

              substituting values we have

                              1.0 * 10^{4} kJ  = (50kg) (4.18kJ/kg^{o}C ) ΔT

                              ΔT = \frac{1.0 * 10^{4}kg}{(50kg)(4.18kJ/kg^{o} C)}    

                                   =  47.85°C  

To maintain the normal  body temperature (98.6F = 37°C) the amount of heat released by metabolism activity must be utilized for evaporation of some amount of water

Hence

        Amount of water that must be evaporated =\frac{heat released per day}{heat of vaporization of water}

                                                                      = \frac{1.0* 10^{4}kJ}{2.41kJ/g} \\= 4149.38g\\=4.15kg  

          Note  (1 kg = 1000 g)

This makes sense because firstly the value obtained is positive  then secondly it is a normal occurrence in the real world that in a place where the temperature is high the body usually produce sweat in order to balance its internal temperature

7 0
3 years ago
HELP ASAP!!! THANKS!!!
sp2606 [1]
44÷22=2 g/cm3 so A is correct answer
4 0
3 years ago
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