Answer:
3.61 m
Explanation:
First, find how long it takes to land.
Given (in the y direction):
Δy = 16 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(16 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.81 s
Given (in the x direction):
v₀ = 2.0 m/s
a = 0 m/s²
Find: Δx
Δx = v₀ t + ½ at²
Δx = (2.0 m/s) (1.81 s) + ½ (0 m/s²) (1.81 s)²
Δx = 3.61 m
given,
mass of the skier = 70.1 Kg
angle with horizontal, θ = 8.6°
magnitude of the force,F = ?
a) Applying newton's second law
velocity is constant, a = 0
b) now, when acceleration, a = 0.135 m/s²
velocity is constant, a = 0.135 m/s₂
I think the answer to your question is true
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