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blagie [28]
3 years ago
8

A ball is thrown horizontally from a 16 m -high building with a speed of 2.0 m/s .

Physics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

3.61 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(16 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.81 s

Given (in the x direction):

v₀ = 2.0 m/s

a = 0 m/s²

t = 1.81 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.0 m/s) (1.81 s) + ½ (0 m/s²) (1.81 s)²

Δx = 3.61 m

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Convert 3402kgm/s to 20000Newtons
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The best I can do for you is something like this:

Let's say you have a moving object with 3,402 kg-m/s of momentum, and you want to STOP it completely.  You want to stand in front of it and push back on it, hard enough and for long enough to CHANGE its momentum from 3,402 kg-m/s to zero.

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The amount you'll change its momentum is called the <u><em>impulse</em></u> you give it.  The quantity of impulse is (force) x (length of time you push on it).

So you need to keep pushing it back for (T seconds) long enough so that

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Divide each side of that equation by (20,000 Newtons). Then it says:

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<em>T = 0.1701 second</em>

And that's how you provide just enough impulse to stop the flying object ... push on it with 20,000 Newtons of force for exactly 0.1701 second, and it loses all its momentum and falls out of the air onto the ground at your feet.

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