Radar, Radio, Microwaves are examples of this kind of energy im so confused on what energy this is

According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational fo

hodyreva [135]

Answer:

C. Plant A orbits its star faster than Plant B

Explanation:

Did it on study island

7 0

2 years ago

The convection currents in the asthenosphere cause the movement of the

MA_775_DIABLO [31]

Convection currents generated within the asthenosphere push magma upward through volcanic vents and spreading centres to create new crust. Convection currents also stress the lithosphere above, and the cracking that often results manifests as earthquakes.

7 0

3 years ago

because lighting heats up the surrounding air slowly, it realationship to thunder is currently unknown true or false

NeTakaya

Answer:

False

Explanation:

8 0

2 years ago

A deciliter is how many times larger than a millimeter?

jarptica [38.1K]

Milliliter centiliter deciliter liter dekaliter hectoliter kiloliter

All related by 10's every move to the right is 10x larger than the one to its left

Since deciliter is two steps away from milliliter it is 10 x 10 or 100 times as large.

If the question is meant to be a trick then the answer is 99x larger.

It should read "A deciliter is how many milliliters" ofr "a milliliter is how much of a deciliter?"
Once you say larger than you could be confusing subtraction with multiplication. How much larger than 30 is 3? Answer is clearly 27. How many times as large as 3 is 30? Answer is clearly 20. How many times larger than 3 is 30? Hmmmm? Which one of the two does he mean?
I am sure your teacher meant you to consider multiplication, but just in case, I included the "trick" answer.

8 0

3 years ago

On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik

Anon25 [30]

a) $4.62\cdot 10^{14} J$

b) 0.110 megatons

c) 8.46 bombs

Explanation:

a)

The energy lost by the meteorite is equal to the difference between its final kinetic energy and its initial kinetic energy:

$\Delta K=K_f-K_i$

Which can be rewritten as:

$\Delta K=\frac{1}{2}mv^2-\frac{1}{2}mu^2$

where:

$m=3.2\cdot 10^6 kg$ is the mass of the meteorite

$v=0$ is the final speed of the meteorite

$u=17 km/s = 17,000 m/s$ is the initial speed of the meteorite

Substituting the values into the equation, we found the loss in energy of the meteorite:

$\Delta K=0-\frac{1}{2}(3.2\cdot 10^6)(17000)^2=-4.62\cdot 10^{14} J$

So, the energy lost by the meteorite is $4.62\cdot 10^{14} J$

b)

The energy equivalent to 1 megaton of TNT is

$E_{TNT}=4.2\cdot 10^{15} J$

Here the energy lost by the meteorite is

$E=4.62\cdot 10^{14} J$

Therefore, in order to write the energy lost by the meteorite as a multiple of the energy of 1 megaton of TNT, we have to divide the energy lost by the meteorite by the energy equivalent to 1 TNT; we find:

$\frac{E}{E_{TNT}}=\frac{4.62\cdot 10^{14}}{4.2\cdot 10^{15}}=0.110$