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OverLord2011 [107]
3 years ago
12

Does anyone know how to do this?​

Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Explanation:

By Hooke's Law,

F=kx

The only force acting here is weight, and x is the extension of the string (you need to convert this to mm) so

mg=kx

(0.15)(9.81)=k ((420-300)x10^-3)

Then just solve this equation.

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mass of the box = 20 kg

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F_s = \mu_s N

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F_s = 156.8 N

similarly kinetic friction on it

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F_k = 0.30* 20 * 9.8

F_k = 58.8 N

now the weight of the suspended block will be

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so here the weight of the suspended block is less than the limiting friction on it

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Natasha2012 [34]
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How is friction reduced between an air hockey puck and the table.
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Answer:

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Explanation:

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When analyzing the statement the student has some problems.

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