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Gre4nikov [31]
3 years ago
15

When solid mg metal is put into an aqueous solution of snso4, solid sn metal and a solution of mgso4 result. write the net ionic

equation for the reaction?
Chemistry
2 answers:
kvv77 [185]3 years ago
5 0
Mg(s) + SnSO₄(aq) = MgSO₄(aq) + Sn(s)

Mg + Sn²⁺ + SO₄²⁻ = Mg²⁺ + SO₄²⁻ + Sn

Mg + Sn²⁺ = Mg²⁺ + Sn
mr_godi [17]3 years ago
4 0

Answer: Mg(s)+Sn^{2+}(aq)\rightarrow Mg^{2+}(aq)+Sn(s)

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:-

Mg(s)+SnSO_4(aq)\rightarrow MgSO_4(aq)+Sn(s)

The complete ionic equation is:

Mg(s)+Sn^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+SO_4^{2-}(aq)+Sn(s)

The SO_4^{2-} ions which are present on both the sides of the equation are not involved in net ionic equation.

Hence, the net ionic equation is:

Mg(s)+Sn^{2+}(aq)\rightarrow Mg^{2+}(aq)+Sn(s)

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garik1379 [7]
Answer:
             V₂  =  1070 mL or 1.07 L

Solution:

Data Given;
                  P₁  =  1170 mmHg

                  V₁  =  915 mL

                  T₁  =  24 °C  +  273 K  =  297 K

                  P₂  =  842 mmHg

                  V₂  =  ?

                  T₂  =  - 23 °C  +  273 K  =  250 K

According to Ideal gas equation,

                       P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for V₂,

                       V₂  =  P₁ V₁ T₂ / P₂ T₁

Putting Values,

                       V₂  = (1170 mmHg × 915 mL × 250 K) ÷ (842 mmHg × 297 K)

                       V₂  =  1070 mL or 1.07 L
5 0
3 years ago
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Diano4ka-milaya [45]
The balanced chemical reaction is given as follows:

<span>2 KClO3(s) → 2 KCl(s) + 3 O2(g)

The starting amount of the reactant are given above. These values would be used for the calculations. We do as follows:

</span>2.72 g KClO3 (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 1.06 g O2
<span>
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<span>
83.6 kg KClO3 (1000g / 1kg) </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 3275.76 g O2
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4 0
2 years ago
Read 2 more answers
Which of the following best describes an empirical formula?
Monica [59]

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

      C₂H₆O₂ Consist of  Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                         2 : 6 : 2

Divide the ratio by two to get simplest ratio

                          C : H : O

                         2/2 : 6/2 : 2/2

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₂H₆O₂ = CH₃O

So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

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