1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RideAnS [48]
3 years ago
8

Which statement is true of forces?

Physics
1 answer:
jasenka [17]3 years ago
8 0
FORCES HAVE  STRENGTH AND DIRECTION 
You might be interested in
What is the gravitational potential energy of a 150 kg object suspended 5m above the Earth's surface
ella [17]
The gravitational potential energy referred to the ground level is given by
U=mgh
where m is the mass of the object, g=9.81 m/s^2 is the gravitational acceleration and h is the height of the object with respect to the ground.

Therefore in our problem the potential energy is
U=(150 kg)(9.81 m/s^2)(5 m)=7357.5 J
6 0
3 years ago
Kieran takes off from rest down a 50 m high, 10° slope on his jet-powered skis. The skis have a thrust of 280 N parallel to the
xz_007 [3.2K]

Answer:0.46

Explanation:

Given

Initial height h=50 m

inclination \theta =10^{\circ}

Thrust=280 N

combined mass of kieran and skis m=50 kg

Speed at the bottom v=40 m/s

From Work Energy Theorem

Work done by all the force is equal to change in kinetic Energy

W_{gravity}+W_{friction}+W_{thrust}=\frac{1}{2}mv^2-0------------1

distance traveled along the slope x=\frac{50}{\sin 10}=287.93 m

W_{gravity}=mgh=50\times 9.8\times 50=24500 J

W_{thrust}=F\times x=280\times 287.93=80,620.4 J

W_{friction}=-\mu mg\cos 10

substitute in 1

24,500+80,620.4+W_{friction}=\frac{1}{2}\times 50\times 1600

W_{friction}=40,000-24,500-80,620.4

-\mu \cdot 50\times 9.8\times 287.93=-65,120.4

\mu =\frac{65,120.4}{141,085.7}=0.46

8 0
3 years ago
Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer
Elena-2011 [213]

Answer:

--------------------------------

Explanation:

4 0
3 years ago
A suspended object A is attracted to a charged object B, can one conclude that A is charged? Explain
irinina [24]

Explanation:

In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B

Example =

If Object B is Negatively Charged, the Object A should be Positively Charged

If the Object B is Positively Charged, the Object A should be Negatively Charged

Sometimes it can Mix as a Neutral as well

Hope this Helps

5 0
3 years ago
Which of these components is present in this circuit schematic?
Svetlanka [38]
Its resistor :}...............

4 0
3 years ago
Read 2 more answers
Other questions:
  • When the man inside the treadmill steps up, what force pulls home back? In what direction does this force move him?
    10·1 answer
  • Which statement is true for light passing into a medium that is more optically dense than the first medium through which it past
    14·1 answer
  • In 1909 Robert Millikan was the first to find the charge of an electron in his now-famous oil drop experiment. In the experiment
    14·1 answer
  • Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 2.1×104 m/s when at a distance
    9·1 answer
  • You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
    6·1 answer
  • Hmmm... Who can answer this question?<br><br>How did life begin?<br><br>Just a practice
    9·1 answer
  • A cyclist and his bicycle have a combined mass of 85 kg. If he is moving at
    15·1 answer
  • Why is an important to come up with a plan for how are you to respond to negative peer pressure before the situation happens
    11·1 answer
  • D<br>Iylpst any three properties of 9.​
    11·1 answer
  • a father pulls his young daughter on a sled (where the combined mass of his daughter and the sled are 40 kg) with a constant vel
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!