Answer:
Train will 588.215 m ahead of automobile
Explanation:
We have given initially speed of both train and automobile is same as 23 m/sec
After that acceleration of automobile
Initial velocity u = 23 m/sec
Final velocity v = 0 ( as it comes to rest )
According to first law of motion
v=u+at
t = 5.75 sec
Now according to third law of motion
s = 66.125 m
Now automobile accelerates at with acceleration
Initial velocity u = 23 m/sec
Final velocity v = 23.2 m/sec
So
Distance traveled by automobile in 0.0956 sec
So total distance traveled by automobile = 66.125+2.208 = 68.333 m
Total time = 5.75 +22.7+0.0956=28.545 sec
Sp distance traveled by train in 28.545 sec
= 28.545×23 = 656.548 m
So distance between automobile and train = 656.548 - 68.33=588.215 m
So train will 588.215 m ahead of automobile