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GarryVolchara [31]
3 years ago
10

What are the four factors that influence how fast the water will flow

Physics
1 answer:
lesya [120]3 years ago
8 0
<span>Viscosity is a property of the water which opposes the relative motion between the two surfaces of the water that are moving at different velocities. In simple terms, viscosity of water means friction between the molecules of water. Factors affecting viscosity of water
1. TemperatureTemperature strongly influences a fluid’s viscosity. Viscosity decreases with increasing temperature and vice versa.
2. PressureNormally, an increase in pressure causes viscosity to increase.
3. ConcentrationConcentration has also direct relation with the viscosity.<span>
</span></span>
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How can you tell that this paragraph uses a quotation?<br> Check all that apply?
Debora [2.8K]

Answer- There are two reasons that we know quotations have been used first is the use of of name of the person who quoted it and secondly the quotation is written inside the quotation marks.

Explanation- Quotation is nothing but using a line that has been already quoted by someone somewhere. Such sentences are normally written inside quotation marks. In the above given paragraph the name of the person who quotes the sentence is also given hence we know that our quotation has been used.

8 0
3 years ago
In the rectangle to the left, if
Margarita [4]

perimeter of a rectangle = 2(L+B)

90=2(L+B)

90/2=L+B

45=L+B

7 0
3 years ago
Which force is always directed toward the center of a circle?
vova2212 [387]
The answer is D. centripetal force
This definition of centripetal force is a force acting towards the center of an object moving in a circular motion. Acceleration is the rate of which velocity changes over a period of time. If you pick a point on say a rotating circle and find the tangential velocity at each point it goes through, the acceleration would be towards the middle. 
6 0
3 years ago
Using a scale of 1 cm to represent 10 N, find the size and direction of the resultant of forces of 50 N
marta [7]

Answer:

74.31\ \text{N}

16.59^{\circ}

Explanation:

P = 50 N

Q = 30 N

\theta = Angle between the vectors = 45^{\circ}

Resultant is given by

R=\sqrt{P^2+Q^2+2PQ\cos\theta}\\\Rightarrow R=\sqrt{50^2+30^2+2\times 50\times 30\times \cos45^{\circ}}\\\Rightarrow R=74.31\ \text{N}

Angle of resultant

\phi=\tan^{-1}\dfrac{Q\sin\theta}{P+Q\cos\theta}\\\Rightarrow \phi=\tan^{-1}\dfrac{30\times \sin45^{\circ}}{50+30\cos45^{\circ}}\\\Rightarrow \phi=16.59^{\circ}

Magnitude of the resultant is 74.31\ \text{N}

Direction of the resultant is 16.59^{\circ}

4 0
3 years ago
A car tire contains 0.0380m3 of air at a pressure of 2.20×105N/m2 (about 32 psi). How much more internal energy does this gas ha
emmasim [6.3K]

Answer:

\Delta U = 11305 J

Explanation:

As per ideal gas equation we know that

PV = nRT

here we know that

P = 2.20 \times 10^5 Pa

V = 0.0380 m^3

now we have

nRT_1 = (2.20 \times 10^5)(0.0380) = 8360 J

now for other case at zero gauge pressure we have

P = 1.01 \times 10^5 Pa

V = 0.0380 m^3

we have now

nRT_2 = (1.01 \times 10^5)(0.0380) = 3838 J

now the difference in internal energy of air is given as

\Delta U = \frac{5}{2}nR\Delta T

\Delta U = \frac{5}{2}(8360 - 3838)

\Delta U = 11305 J

6 0
3 years ago
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