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2 years ago

What are the four factors that influence how fast the water will flow

1 answer:

8 0

Viscosity is a property of the water which opposes the relative motion between the two surfaces of the water that are moving at different velocities. In simple terms, viscosity of water means friction between the molecules of water. Factors affecting viscosity of water
1. TemperatureTemperature strongly influences a fluid’s viscosity. Viscosity decreases with increasing temperature and vice versa.
2. PressureNormally, an increase in pressure causes viscosity to increase.
3. ConcentrationConcentration has also direct relation with the viscosity.

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A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator

Ivenika [448]

Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

5 0

3 years ago

The compound ethylene (C2H4) is represented by this diagram. What statement best describes the arrangement of the atoms in an et

Effectus [21]

Answer: The correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.

Explanation:

Ethylene is a compound given by the chemical formula $H_2C=CH_2$ .

The bond present between hydrogen and carbon atoms or carbon and carbon atoms are covalent bonds. A covalent bond is formed by the sharing of electrons between the atoms combining.

A double bond is present between carbon and carbon atoms. So 2 pairs of electrons are shared which means in total of 4 electrons are shared.

Bond present between hydrogen and carbon atoms are single bonds. So, a pair of electrons is shared which means that in total of 2 electrons are shared.

Hence, the correct answer is two electrons are shared between each hydrogen atom and the carbon atom bonded to it, and four electrons are shared between the carbon atoms.

6 0

3 years ago

Read 2 more answers

An investigator collects a sample of a radioactive isotope with an activity of 490,000 Bq.48 hours later, the activity is 110,00

Daniel [21]

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ $A = A_0 e^{- \lambda t}$

or,

⇒ $\frac{A}{A_0}=e^{-\lambda t}$

By taking "ln", we get

⇒ $ln \frac{A}{A_0}=- \lambda t$

By substituting the values, we get

⇒ $-ln \frac{110000}{490000} = -48 \lambda$

⇒ $-1.4939=-48 \lambda$

$\lambda = 0.031122$

As,

⇒ $\lambda = \frac{ln_2}{\frac{T}{2} }$

then,

⇒ $\frac{ln_2}{T_ \frac{1}{2} } =0.031122$

⇒ $T_\frac{1}{2}=\frac{ln_2}{0.031122}$

$=22.27 \ hours$

3 0

2 years ago

jack wants to find out which laundry detergent cleans the best ( Gain, Tide, or Purex). So, he takes a cotton sheet and cuts it

dezoksy [38]

the independent variables are the different laudry detergent

the dependent variable is color of the cloth after washing

the control variables are the amount of water added and by washing one cloth b just water

hypothesis: the cloth washed with laundry detergent is cleaner than the cloth that is just washed by water.

6 0

3 years ago

Read 2 more answers

Two deuterium nuclei, H, fuse to produce a tritium nucleus, H, and a hydrogen nucleus. A neutral deuterium atom has a mass of 2.

Nesterboy [21]

Answer: The amount of energy released in the process is 4.042 MeV.

Explanation:

The chemical reaction for the fusion of deuterium nucleus follows the equation:

$_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _1^3\textrm{H}+_1^1\textrm{H}$

Atomic mass of the nucleus also contains some mass of the electrons.

Mass of electron in $MeV/c^2$ is $0.511MeV/c^2$

Calculating the mass of deuterium nucleus:

$m(_1^2\textrm{H})=(2.014102u)\times (931.494MeV/c^2.u)-\text{Mass of electron}$

So, initial mass of the reaction = $2[(1876.124MeV/c^2)-(0.511MeV/c^2)]=3751.226MeV/c^2$

Calculating the mass of tritium nucleus:

$m(_1^3\textrm{H})=(3.106049u)\times (931.494MeV/c^2.u)-\text{Mass of electron}$

$m(_1^3\textrm{H})=(3.106049u)\times (931.494MeV/c^2.u)-(0.511MeV/c^2)=2803.921MeV/c^2$

So, final mass of the reaction = $2803.921-[(1.007267u\times 931.494MeV/c^2.u)]=3747.184$

Difference between the masses of the nucleus:

$\Delta m=m_{initial}-m_{final}\\\\\Delta m=(3751.226-3747.184)MeV/c^2=4.042MeV/c^2$

Energy released in the process is calculated by using Einstein's equation, which is:

$E=\Delta mc^2$

Putting value of $\Delta m$ in above equation, we get:

$E=(4.042MeV/c^2)\times c^2\\\\E=4.042MeV$

Hence, the amount of energy released in the process is 4.042 MeV.

4 0

3 years ago