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2 years ago

13

A physicist hangs a 150-g object on a spring whose spring constant is a value of 13.22 Newtons/meter and has a spring force of 2

0N. How far does the spring stretch?

1 answer:

Nataly_w [17]2 years ago

4 0

Answer:

so the answer is this because the answer is that

Explanation:

and the reason why the answer is this and that is because the answer is that

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3 years ago

Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s

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Answer:

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe ..... (1)

T Cosθ = mg .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

$tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}$

$tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}$

$tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}$

$tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}$

As θ is very small, so tanθ and Sinθ is equal to θ.

$\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}$

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

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2 years ago

As an interstellar cloud of hydrogen gas shrinks in size, its rate of rotation

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Answer:

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