Explanation:
It is given that,
Length of the rod, l = 14 cm = 0.14 m
Charge on the rod, 
We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m
Electric field at the axis of the rod is given by :
Where
is the linear charge density of the rod,
E = -7493170.57 N/C
or
Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.
100cm to go in 600 secs = 10mins
2 positive, 1 negative .... net 1 positive per step
Electromagnetic waves<span> transfer energy without going through a medium. ... Sometimes, a </span>transverse wave<span> and a </span>longitudinal wave can combine to form<span>another </span>kind<span> of </span>wave<span> called a surface </span>wave<span>. </span>Transverse Waves<span>. </span>Waves<span> in which the particles vibrate in an up-and-down motion
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Answer:
3 quarters of the world likes pizza. (75%) and the remaining quarter of people (25%) dont like pizza.
Answer:
497.143 nm.
Explanation:
Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.
The solution to the question is through the use of the formula in the equation (1) below;
Sin θ = m × λ. ---------------------------------(1).
Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).
Also, m × λ = dc/ B -------------------------------------------(2).
We are to find the second wavelength, therefore;
λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).
Where c1 and c2 are the order maximum and m = order numbers. Hence;
λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.
