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3 years ago

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A 5 kg box is sitting on a rough wooden surface. The coefficient of static friction between the box and surface is 0.6. If the n

ormal force on the box is 50 N, calculate the force of friction which must be overcome to move the box. Round your answer to the nearest whole number.

1 answer:

arlik [135]3 years ago

5 0

The force of friction needed to overcome to move the box is 29.4N

According to Newton's second law;

$\sum F_x = ma_x\\$

Taking the sum of force along the plane;

$F_m -F_f = ma\\F_m -F_f = 0\\F_m=F_f = \mu R$

This shows that the moving force is equal to the frictional force

Given that

$\mu = 0.6\\R = mg = 49N$

Get the frictional force;

Since

$F_f = \mu R\\F_f = 0.6 \times 49\\F_f = 29.4N$

Hence the force of friction needed to overcome to move the box is 29.4N

Learn more here: brainly.com/question/189856

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582 years ago to 2019

1437

$T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s$

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