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Elis [28]
3 years ago
7

Show that 6^3-1 is divisible by 5 using our identities

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

Step-by-step explanation:

a³-b³=(a-b)(a²+ab+b²)

6³-1=6³-1³=(6-1)(6²+6*1+1²)=5×43

so 6³-1 is divisible by 5.

Harlamova29_29 [7]3 years ago
5 0

\displaystyle 6^3 - 1 = 216 - 1 = 215

The number 215 is divisible by 5 because it ends in 5, according to the <em>divisibility</em><em> </em><em>rules</em>.

I am joyous to assist you anytime.

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