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Elis [28]
3 years ago
7

Show that 6^3-1 is divisible by 5 using our identities

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

Step-by-step explanation:

a³-b³=(a-b)(a²+ab+b²)

6³-1=6³-1³=(6-1)(6²+6*1+1²)=5×43

so 6³-1 is divisible by 5.

Harlamova29_29 [7]3 years ago
5 0

\displaystyle 6^3 - 1 = 216 - 1 = 215

The number 215 is divisible by 5 because it ends in 5, according to the <em>divisibility</em><em> </em><em>rules</em>.

I am joyous to assist you anytime.

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Step-by-step explanation:

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Answer is the third one or C. Can I have brainliest?! Please?!
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find a parameterization for a circle of radius 3 with center (-4,4,1) in a plane parallel to the yz plane. write your parameteri
madam [21]

Answer:

Following are the solution to the question:

Step-by-step explanation:

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6 0
3 years ago
A
kykrilka [37]

Answer:

One possible answer would be they sold 80 student tickets and 30 adult tickets

Step-by-step explanation:

set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make

5x+10y G than or =  700

x+y L than or = 110

The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.

The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.

First find either x or y, in this case finding y was easier

y is g than or = to 30

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With y, plug into the inequality x+y L than or = to 110 to find x

x is less than or = to 80

This means that they sold at most 80 student tickets = $400

Hope this helps!

8 0
2 years ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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