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Elis [28]
3 years ago
7

Show that 6^3-1 is divisible by 5 using our identities

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

Step-by-step explanation:

a³-b³=(a-b)(a²+ab+b²)

6³-1=6³-1³=(6-1)(6²+6*1+1²)=5×43

so 6³-1 is divisible by 5.

Harlamova29_29 [7]3 years ago
5 0

\displaystyle 6^3 - 1 = 216 - 1 = 215

The number 215 is divisible by 5 because it ends in 5, according to the <em>divisibility</em><em> </em><em>rules</em>.

I am joyous to assist you anytime.

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Which transformations could have been used to create A'B'C'? Choose all that apply.
Eduardwww [97]

The correct transformation is a rotation of 180° around the origin followed by a translation of 3 units up and 1 unit to the left.

<h3>Which transformation is used to get A'B'C'?</h3>

To analyze this we can only follow one of the vertices of the triangle.

Let's follow A.

A starts at (3, 4). If we apply a rotation of 180° about the origin, we end up in the third quadrant in the coordinates:

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Now if you look at A', you can see that the coordinates are:

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To go from (-3, -4) to (-4, -1), we move one unit to the left and 3 units up.

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If you want to learn more about transformations:

brainly.com/question/4289712

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2 years ago
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Step-by-step explanation:

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