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2 years ago

Can A fire extinguisher kill A Human Being

2 answers:

3 0

Yes. it could kill someone because they are designed to take the oxygen out of the atmosphere to put out a fire, You can kill a person by suffixation, You can purchase a unit that gives off a harmless vapor that resembles white smoke though.

Andreas93 [3]2 years ago

3 0

It depends if the person was hit with it

You might be interested in

List the protons, neutrons, and electrons for Ge2+<br> Please hurry

Nady [450]

Answer:

32, 30 and 41

Explanation:

The problem here is to find the number of:

Protons, neutrons and electrons in Ge²⁺

In this ion,

We must understand that for a net positive charge to remain on an atom, the number of protons must be greater than the number of electrons.

Ge is Germanium with atomic number of 32;

So the number of protons is 32

Since the atom has lost two electrons;

Number of electrons now is 32 - 2 = 30

Number of neutrons is 41 from the periodic table.

7 0

2 years ago

How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?

nevsk [136]

Answer:

17.5 g

Explanation:

Given data

Mass of solution to be prepared: 50.0 grams

Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

$50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl$

4 0

2 years ago

A 143.1 g sample of a compound contains 53.4 g of carbon, 16.9 g of hydrogen, 43 g of nitrogen, and some amount of oxygen. what

nika2105 [10]

I'm fairly sure this is it 20.82%

6 0

3 years ago

Read 2 more answers

TRUE or FALSE: The rock closest to the ridge is newer and younger than the older rock

alina1380 [7]

Answer:true

Explanation:

7 0

3 years ago

What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?

Sergeu [11.5K]

Answer:

$\large \boxed{\text{b. 1.5 h}}$

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

$\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt$

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

$\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463 h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}$

4 0

3 years ago