$10.50
10 Tickets would be $105.00
$105.00 - $10.50 = $94.50 so 9 Tickets would be $94.50
$105.00 + $94.50 = $199.50
$205.00 - $199.50 = $5.50 which isn't enough for another ticket.
10 Tickets + 9 Tickets = 19 Tickets.
Let's say this number is a:
a*(a-9) = 90
a^2-9a-90 = 0
(a-15)(a+6) = 0
a = 15 or a = -6
Therefor a. would be the correct answer :)
The number of times the image of the octagon will coincide with the preimage during rotation is determined by:
N = R/C
where
N is the number of times the preimage coincided with the rotated image during rotation
R is the angle of rotation
C is the central angle of the regular polygon
For an octagon, the central angle is
C = 360/8 = 45
So,
N = 360 / 45 = 8
Therefore, the rotated image of the octagon will coincide with the preimage 8 times during rotation.
Hello :
<span>-3 = x² + 4x+ 1
x²+4x+4=0
a=1 and b= 4 c= 4
</span><span>b^2 - 4ac = (4)²-4(1)(4) =0
one solution : -b/2a = -4/2 = -2
note : </span>x²+4x+4=0
(x+2)² = 0
x+2 = 0
x= -2
Answer: each girl received 30 stickers.
Step-by-step explanation:
Let x represent the number of stickers that the boys received.
Let y represent the number of stickers that the girls received.
The total number of children was 42. 2/3 of the children were boys. It means that the number of boys were
2/3 × 42 = 28
The number if girls would be
42 - 28 = 14
The total number of stickers that the school principal shared was 840. It means that
28x + 14y = 840- - - - - - - - -1
Each of the boys received the same number of stickers while each girl received twice as many as each boy. It means that
y = 2x
Substituting y = 2x into equation 1, it becomes
28x + 14 × 2x = 840
28x + 28x = 840
56x = 840
x = 840/56
x = 15
y = 2x = 15 × 2
y = 30
