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Andrew [12]
3 years ago
9

The coil of a generator has a radius of 0.14 m. When this coil is unwound, the wire from which it is made has a length of 10.0 m

. The magnetic field of the generator is 0.24 T, and the coil rotates at an angular speed of 34 rad/s. What is the peak emf of this generator?
Physics
1 answer:
adell [148]3 years ago
3 0

Answer:

5.565 V

Explanation:

Radius of coil of generator=r=0.14 m

Length of wire=l=10 m

Magnetic field,B=0.24 T

Angular speed,\omega=34rad/s

We have to find the peak emf of the generator.

N=\frac{l}{2\pi r}=\frac{10}{2\pi\times 0.14}=11

A=\pi r^2=\pi (0.14)^2=0.062m^2

Peak(maximum) induced emf of generator=E_{max}=NBA\omega

Using the formula

E_{max}=11\times 0.24\times 0.062\times 34

E_{max}=5.565 V

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A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate
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Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

           ∑ τ = 0

           F l -x W = 0

           F = \frac{x}{l} \  W

let's calculate

          F = \frac{4}{100}4/100 600

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This can be explained by;  When air is blocked by mountains, it cannot go through these mountains, As it ascends or moves up the mountain, the air then cools as it rises and when it cools to its saturation point, the water vapor condenses and cloud forms.

These clouds formed  are known as orographic clouds, that develop in response to the lifting forced by the topography the earth.

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Find the electric force acting on an alpha particle in a horizontal electric field of 600N/C
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Farmer Brown has sprayed his fields to kill the grasshoppers eating the grass in his pastures. Predict what will happen to the o
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A 72-kg skydiver is falling from 10000 feet. At an instant during the fall, the skydiver
MissTica

Answer:

Approximately 2.31\; \rm m \cdot s^{-2} (assuming that the acceleration due to gravity isg = 9.81\; \rm m \cdot s^{-2}.)

Explanation:

Assuming that g = 9.81\; \rm m \cdot s^{-2} the weight on this 72-kg skydiver would be W = m \cdot g = 72 \; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 706.32\; \rm N (points downwards.)

Air resistance is supposed to act in the opposite direction of the motion. Since this skydiver is moving downwards, the air resistance on the skydiver would point upwards.

Therefore, the net force on this skydiver should be the difference between the weight and the air resistance on the skydiver:

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Apply Newton's Second Law of motion to find the acceleration of this skydiver:

\begin{aligned}a &= \frac{F(\text{net force})}{m} \\ &= \frac{166.32\; \rm N}{72\; \rm kg} = 2.31\; \rm m \cdot s^{-2} \end{aligned}.

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