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3 years ago

When the elements in group 1 are considered in order from top to bottom, each successive element at standard pressure has

2 answers:

6 0

When the elements in group 1 are considered in order from top to bottom, each successive element at a standard pressure has a lower melting point and boiling point. This is because melting and boiling points decrease when the increasing atomic number. The correct answer will be D.

Talja [164]3 years ago

4 0

Answer is: d. a lower melting point and boiling point.

Alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

Bond between these elements is metallic bond.

Both the melting and boiling points decrease down the group 1, because the decrease in the strength of each metallic bond.

From top to bottom, atomic radius increase and the distance between the nucleus and delocalized electrons increases, so metallic bond is weaker (attractions fall).

Metallic bond is formed between electrons and positively charged metal ions.

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3 years ago

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3 years ago

Explain the process of rainwater harvesting with its advantages .

leva [86]

Answer:

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4 0

3 years ago

Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules. Several other gases make up the remaining 1% of air molecules.

kherson [118]

Answer:

The partial pressure of the other gases is 0.009 atm

Explanation:

Step 1: Data given

Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules and 1% of other gases.

The atmospheric pressure = 0.90 atm

Step 2: Calculate mol fraction

If wehave 100 moles of air, 78 moles will be nitrogen,

21 moles will be oxygen, and 1 mol will be other gases.

Mol fraction = 1/100 = 0.01

Step 3: Calculate the partial pressure of the other gases

Pgas = Xgas * Ptotal

⇒ Pgas = the partial pressure = ?

⇒ Xgas = the mol fraction of the gas = 0.01

⇒Ptotal = the total pressure of the pressure = 0.90 atm

Pgas = 0.01 * 0.90 atm

Pgas = 0.009 atm

The partial pressure of the other gases is 0.009 atm

4 0

4 years ago

[25 pts] When a 14.2g sample of a compound containing only mercury and oxygen is decomposed, 13.2g of Hg is obtained. What is th

Agata [3.3K]

Answer:

% composition of Hg = 93 %

% composition of O = 7 %

Explanation:

Data Given:

mass of total sample = 14.2 g

mass of mercury (Hg) = 13.2 g

percent composition of Hg =

percent composition of O =

Solution:

First find mass of oxygen

As this compound only have two components that is oxygen and mercury

upon decomposition it gives 13.2 g mercury

now to find mass of oxygen we have to subtract mass of mercury from total mass of sample

Mass of oxygen = Total mass of sample - mass of Mercury

Mass of oxygen = 14.2 g - 13.2 g

Mass of oxygen = 1 g

Now to find percent composition of Hg and Oxygen

% composition = component mass / total mass of sample x 100. . . .(1)

For % composition of mercury Hg

Put values in equation 1

% composition of Hg = 13.2 g / 14.2 g x 100

% composition of Hg = 93%

For % composition Oxygen (O)

Put values in equation 1

% composition of O = 1 g / 14.2 g x 100

% composition of O = 7 %

6 0

3 years ago