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stira [4]
3 years ago
10

Approximately how many elements combine in different ways to make compounds?

Chemistry
2 answers:
Vlada [557]3 years ago
8 0
Mos commonly 2 elements combine.

examples: H2, O2
erastovalidia [21]3 years ago
6 0

Answer:

Approximately two elements may combine to form compounds, but there may be cases where more than two elements combine to form compounds.

Explanation:

In chemistry, the term compound is defined as a substance formed by the union of at least two elements. There are cases where more than two elements come together to form a compound, but we can say that approximately two elements are used for compound formation. An example of compound is shown in the chemical formulas H2O and FeS represent the compounds water and ferrous sulfide.

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<u>Answer:</u>

The correct answer option is B) 2.0 M.

<u>Explanation:</u>

We are given the number of grams of NaOH (Sodium Chloride) which are dissolved in 750 milliliters of water and we are to find its molarity.

We know the formula of molarity:

<em>Molarity =  (mass * 1000) / (volume * molecular mass)  </em>

Volume = 750 ml = 750 cm^3

Molecular mass = 40  

Mass = 60 grams

Substituting these values in the above formula:

Molarity = \frac{(60*1000)}{750*40} = 2.0 M

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How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

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So,  

k=\frac {ln\ 2}{t_{1/2}}

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<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

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beks73 [17]

Answer:

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