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stira [4]
3 years ago
10

Approximately how many elements combine in different ways to make compounds?

Chemistry
2 answers:
Vlada [557]3 years ago
8 0
Mos commonly 2 elements combine.

examples: H2, O2
erastovalidia [21]3 years ago
6 0

Answer:

Approximately two elements may combine to form compounds, but there may be cases where more than two elements combine to form compounds.

Explanation:

In chemistry, the term compound is defined as a substance formed by the union of at least two elements. There are cases where more than two elements come together to form a compound, but we can say that approximately two elements are used for compound formation. An example of compound is shown in the chemical formulas H2O and FeS represent the compounds water and ferrous sulfide.

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The goal of this experiment is to separate a mixture of two unknown compounds into individual components and to identify the com
kolbaska11 [484]

Answer: Ethyl Ethanoate can be used as a developing solvent. It’s safer.

Explanation:Di ethyl ether should be carefully used because it’s highly flammable and intoxicating when inhaled and can cause explosions because of its high reactivity to air and light.

3 0
3 years ago
→
marin [14]

Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

8 0
3 years ago
_____ NaPO4+_____KOH
Artist 52 [7]
NaPO4 + KOH -> KPO4 + NaOH
already balance
6 0
3 years ago
What do you think is the reason for an increasing atomic radius within one group?
Anna35 [415]

Answer:

As you go down a group on the periodic table, you get more electron shells and therefore a larger atomic radius.

7 0
2 years ago
Read 2 more answers
Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that
svetlana [45]

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

6 0
3 years ago
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