570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students
Answer:
pOH of resulting solution is 0.086
Explanation:
KOH and CsOH are monoacidic strong base
Number of moles of 
in 375 mL of 0.88 M of KOH = 
= 0.33 moles
Number of moles of in 496 mL of 0.76 M of CsOH = 
= 0.38 moles
Total volume of mixture = (375 + 496) mL = 871 mL
Total number of moles of in mixture = (0.33 + 0.38) moles = 0.71 moles
So, concentration of in mixture, ![[OH^{-}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D)
= 
Hence, ![pOH=-log[OH^{-}]=-log(0.82)=0.086](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E%7B-%7D%5D%3D-log%280.82%29%3D0.086)
Answer:
Volume = 72.7272
Explanation:
if only pressure and volume change, then we can do some simple math to find the answer.
2 x 10 ^ 6 times 1 x 10 ^-5 = 20
pressure and volume must equal 20
20 = 0.275 x volume
20 / 0.275 = new volume
I don't remember significant digits but your volume is 72.72727272 just repeated
I guess you could call them that. In chemistry, we call them Metalloids though.
