Oxygen
Carbon
Sulphur
Magnesium
Chlorine
Phosphorus
Potassium are the elements
<h3>
Answer:</h3>
0.0520 mol Zn
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.40 g Zn
<u>Step 2: Identify Conversions</u>
Molar Mass of Zn - 65.39 g/mol
<u>Step 3: Convert</u>
- Set up:
- Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.051996 mol Zn ≈ 0.0520 mol Zn
Answer:
-1605.1 kJ
Explanation:
The enthalpy of formation is the enthalpy of the reaction that forms the substance only by its constituents, so, substances formed by one element, such as O2, in its ambient temperature phase, have an enthalpy of formation 0.
The enthalpy is a measure of how much heat the system contains, and so, the variation of it measures the heat lost (ΔH <0) or gained (ΔH >0), and for a reaction:
ΔHrxn = ∑ni*ΔHi products - ∑ni*Hi reactants
Where ni represents the coefficient of the substance, so by the data given:
ΔHrxn = [2*(-241.82) + (-393.5)] - [-74.6]
ΔHrxn = -802.54 kJ/ mol of CH4
Thus, the heat released is the enthalpy multiplied by the number of moles of CH4:
Q = -802.54*2
Q = -1605.1 kJ
The sugar dissolved in the kool aid, <span>become or cause to become incorporated into a liquid so as to form a solution. the proof that the sugar is present because it made the kool aid taste sweeter which is a property of the sugar. to get back the sugar we must heat the kool aid until sugar residue will remain</span>