Answer:
The concentration of NaOH solution is 3,65M
Explanation:
The neutralization of NaOH with HCl is:
NaOH + HCl → NaCl + H₂O
You are titrating 12,67 mL HCl 2,74M with your NaOH solution, the moles of HCl in the beaker are:
12,67 mL ≡ 0,01267L× = <em>0,0347 moles HCl </em>≡ 0,0347 moles NaOH
The volume that you require for total neutralization of 12,67 mL HCl 2,74M is:
13,65 mL - 4,50 mL = <em>9,50 mL </em>≡ 0,0095L
Thus, the concentration of NaOH solution is:
= <em>3,65M</em>
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I hope it helps!
