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3 years ago

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Physics

1 answer:

ladessa [460]3 years ago

5 0

Answer:

Earth - 1,3,7,10,11,12

venus- 2,4,5,6

both - 8,9,10

Explanation:

hope that the answer will helpful.

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A ball starts from rest and accelerates at 0.460 m/s2 while moving down an inclined plane 8.85 m long. When it reaches the botto

Ivahew [28]

Answer:

$V=2.8534m/s \approx 3m/s$

Explanation:

From the question we are told that

Acceleration $a=0.460m/s$

Distance traveled $S_1=8.5m$

Distance traveled $S_2=15.6m$

Generally the velocity of the ball at the bottom of the first plane V is mathematically given by

$v^2=2as$

$v=\sqrt{2as}$

$V=\sqrt{2*0.460*8.85}$

$V=2.8534m/s \approx 3m/s$

6 0

3 years ago

a 0.0215m diameter coin rolls up a 20 degree inclined plane. the coin starts with an initial angular speed of 55.2rad/s and roll

marissa [1.9K]

Answer:

$h = 0.0362\,m$

Explanation:

Given the absence of non-conservative force, the motion of the coin is modelled after the Principle of Energy Conservation solely.

$U_{g,A} + K_{A} = U_{g,B} + K_{B}$

$U_{g,B} - U_{g,A} = K_{A} - K_{B}$

$m\cdot g \cdot h = \frac{1}{2}\cdot I \cdot \omega_{o}^{2}$

The moment of inertia of the coin is:

$I = \frac{1}{2}\cdot m \cdot r^{2}$

After some algebraic handling, an expression for the maximum vertical height is derived:

$m\cdot g \cdot h = \frac{1}{4}\cdot m \cdot r^{2}\cdot \omega_{o}^{2}$

$h = \frac{r^{2}\cdot \omega_{o}^{2}}{g}$

$h = \frac{(0.0108\,m)^{2}\cdot (55.2\,\frac{rad}{s} )^{2}}{9.807\,\frac{m}{s^{2}} }$

$h = 0.0362\,m$

3 0

3 years ago

A 142 kg boulder is located near the edge of a cliff 25 m above the ground. What is the gravitational potential energy of the bo

jarptica [38.1K]

PE = mass * height * 9.81
PE = 142 * 25 * 9.81
PE = 34825.5 J

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3 years ago

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NEED HELP ASAP!!!! DUE in 5 MINS!!!! $20 in the ratio 1 to 4 WILL GIVE BRAINLIEST

rusak2 [61]

Answer:

$4 : $16

Explanation:

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Julie carries an 8.0-kg suitcase as she walks 18 m along an inclined walkway to her hotel room at a constant speed of 1.5 m/s. T

Colt1911 [192]

In physics, a force is said to do work if, when acting, there is a displacement of the point of application in the direction of the force. For example, when a ball is held above the ground and then dropped, the work done on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). so in the proble, She does NO work since the force she applies to the case is vertical and the direction of motion is horizontal. Work is the force times the parallel distance

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3 years ago

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