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3 years ago

NEED HELP ASAP!!!! DUE in 5 MINS!!!!$20 in the ratio 1 to 4 WILL GIVE BRAINLIEST

Physics

2 answers:

rusak2 [61]3 years ago

8 0

Answer:

$4 : $16

Explanation:

Mekhanik [1.2K]3 years ago

7 0

Answer: 10:20

Explanation:

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A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o

dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is $m_1 = 81.14 \ kg$

Explanation:

From the question we are told that

Mass of the first block is $m_1 = 100 \ kg$

The height is $s = 1.0 \ m$

The time it takes it is $t = 1.40 \ s$

Generally from kinematic equation

$s = ut + \frac{1}{2} at^2$

Here u is the initial velocity which zero given that it was at rest initially

$s = 0 * t + \frac{1}{2} at^2$

=> $s = \frac{1}{2} at^2$

=> $1 = \frac{1}{2}* a * (1.40 )^2$

=> $a = 1.0204 \ m/s^2$

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is mathematically represented as

$mg - T = ma$

=> $T = m g - ma$

=> $T = m(g - a)$

=> $T = 877.96 \ N$

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is mathematically represented as

$T - m_1g = m_1 a$

=> $877.96 = m_1 (a + g)$

=> $877.96 = m_1 (1.0204 + 9.8 )$

=> $m_1 = 81.14 \ kg$

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Answer:

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3 years ago

NEED HELP ASAP!!!! DUE in 5 MINS!!!!$20 in the ratio 1 to 4 WILL GIVE BRAINLIEST ​

NEED HELP ASAP!!!! DUE in 5 MINS!!!!$20 in the ratio 1 to 4 WILL GIVE BRAINLIEST