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Lostsunrise [7]
3 years ago
15

What is your least favorite candy? Explain

Physics
2 answers:
aev [14]3 years ago
7 0

Answer:

My least favorite is whoppers.....Trust me i love chocolate, but not when it taste like chalk......

attashe74 [19]3 years ago
7 0

Answer:

I don't eat any candy, it really isn't good for the environment at all, but my least, <em>least</em> favorite of all lollipops.

Explanation:

If you think about it, lollipops are made with sugar, artificial flavoring and artificial color. <em>2.4 BILLION</em> lollipops are sold every year, causing damage to an average Americans health rate. They are terrible for the teeth as well, since the refined sugar seeps into weak spots of the canal. It affects the metabolic rate too, and in general, is not good to consume whatsoever.

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After a meal.
Tema [17]

Answer:

B.

1-3hours

Explanation:

This is because a diabetic patients have increased blood sugar or glucose concentration. After eating a meal, the blood glucose concentration will be increased as it is been accumulated . Therefore it is best diabetic patient exercise at that hour to reduce it's blood glucose concentration.

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Explain how airplane wings and the wings of birds affect the air flowing over them to produce lift
d1i1m1o1n [39]
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melomori [17]
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Read 2 more answers
vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

3 0
3 years ago
Help
malfutka [58]
The answer for this is 1200N
6 0
3 years ago
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