Answer:
The correct option is: Cost of materials used in manufacture
Explanation:
There are two types of costs of an object: the internal costs and the external costs.
The internal cost of an object is the direct monetized cost. It refers to the cost involved in the <u>production or manufacturing of a given objec</u>t. Example: labor, <u>material required</u>, equipment, energy, and overhead expenses.
Part A
75.0 mL of 0.10 M HF; 55.0 mL of 0.15 M NaF
This combination will form a buffer.
Explanation
Here, weak acid HF and its conjugate base F- is available in the solution
Part B
150.0 mL of 0.10 M HF; 135.0 mL of 0.175 M HCl
This combination cannot form a buffer.
Explanation
Here, moles of HF = 0.15 x 0.1 = 0.015 moles
Moles of HCl = 0.135 x 0.175 = 0.023
Since HCl is a strong acid and the number of HCl is higher than HF. This prevents the dissociation of HF and the conjugate base F- will not be available in the solution
Part C
165.0 mL of 0.10 M HF; 135.0 mL of 0.050 M KOH
This combination will form a buffer.
Explanation
Moles of HF = 0.165 x 0.1 = 0.0165 moles
Moles of KOH = 0.135 x 0.05 = 0.00675 moles
Moles of KOH is not sufficient for the complete neutralization of HF. Thus weak acid HF and its conjugate base F- is available in the solution and form a buffer
Part D
125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 M CH3NH3Cl
This combination will form a buffer
Explanation
Here, weak acid CH3NH3+ and its conjugate base CH3NH2 is available in the solution and form a buffer
Part E
105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl
This combination will form a buffer
Explanation
Moles of CH3NH2 = 0.105 x 0.15 = 0.01575 moles
Moles of HCl = 0.095 x 0.1 = 0.0095 moles
Thus the HCl completely reacts with CH3NH2 and converts a part of the CH3NH2 to CH3NH3+. This results weak acid CH3NH3+ and its conjugate base CH3NH2 is in the solution and form a buffer
Octane is the resistance of the burning of gasoline
Some of the properties that will change as the biological membrane composed primarily of phospholipids change from the saturated to unsaturated fatty acid tails of the phospholipid would include, permeability of the membrane, this will cause the membrane to be more fluid and not remain as controlling of the materials. The membrane will ultimately become poor in regulating ions and other materials from coming into the cell, as the phospholipids are not tightly packed due to them being unsaturated and having carbon double bonds within them. This can also affect the overall shape of the plasma membrane as well, causing it to be not as structured, and more fluid,
Answer:
B. More reactant is added.
Explanation:
The question basically asks at which condition would the forward reaction be favoured.
The law of equilibrium states when a system at equilibrium is disturbed by, it would annul that change. In order to increase the forward reaction, more of the reactant should be added. In order to annul this change, the system would have to favour the reaction that deals with reducing the amount of reactant added.
The correct option is;
B. More reactant is added.
