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3 years ago

A sample of gas consists of 4.0 moles, and exists at stp. What is the volume of the gas?

Chemistry

2 answers:

faust18 [17]3 years ago

6 0

Answer:

The volume of the gas is 89.60

Explanation:

When converting from moles to volume, you would multiply by 22.4 because 1 mole equals 22.4 liters at STP.

So...

4.0 moles * 22.4 liters =

89.60 liters

stiv31 [10]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf 89.6 \ liters}}$

Explanation:

At STP (standard temperature and pressure), all gases have a volume of 22.4 liters per mole.

$\frac {22.4 \ L }{1 \ mol }$

Multiply by the given number of moles, 4.0

$4.0 \ mol *\frac {22.4 \ L }{1 \ mol }$

The moles will cancel out. The 1 in the denominator can be ignored, so this becomes a simple multiplication problem.

$4.0 * {22.4 \ L }=89.6 \ L$

4.0 moles of a gas at STP have a volume of 89.6 liters.

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7. If a waste container has 87.0 mL of 0.234 M acetic acid, how many milliliters of 2.00 M sodium

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$V_{base}=10.2mL$

Explanation:

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Thus, we can compute the volume of sodium hydroxide (base) as follows:

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8 0

3 years ago

What is/are the product(s) of a neutralization reaction of a carboxylic acid?

jekas [21]

RCOOH + NaOH → RCOONa + H₂O (salt and water)

RCOOH + OH⁻ → RCOO⁻ + H₂O

3 0

4 years ago

For the reaction

azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH → 3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

Number of moles = 0.063 mol

Now we will compare the moles of Cl₂ with NaCl.

Cl₂ : NaCl

2 : 3

0.063 : 3/2×0.063 =0.095 mol

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.095 mol × 58.5 g/mol

Mass = 5.56 g

7 0

2 years ago