1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iris [78.8K]
2 years ago
11

If given 5.98 x 10^24 atoms of Copper, how many kilograms do you have?

Chemistry
1 answer:
Rufina [12.5K]2 years ago
7 0

Explanation:

guyvuyvyubi goyuvguvuvgjovovvjjgvgviyvugvygvyivguvugbugbubuggvugvugbgububjhbjhbkhnijninjknjknkjjknnjknjinihnhibibi

You might be interested in
What is the density of 19.2 g of oak that has a volume of 25.7 cm3?
andreyandreev [35.5K]

Density = Mass/Volume

19.2/25.7

= 0.747 or 0.75

7 0
3 years ago
Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en
Bezzdna [24]

Answer:

  • 10.19 g CO₂
  • 4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

  • C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:

  • 1 gallon = 3.785 L
  • 1 L = 1000 mL

Now we<u> convert 1.24 gallons to mL</u>:

  • 1.24 gallon * \frac{3.785L}{1gallon} *\frac{1000mL}{1L} = 4693.4 mL

We <u>calculate the mass of Octane</u>:

  • 4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:

  • CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * \frac{8molCO_{2}}{1molOctane} * 44 g/mol =  10.19 g CO₂
  • H₂O ⇒ 3.30 g Octane ÷ 114g/mol * \frac{9molH_{2}O}{1molOctane} * 18 g/mol = 4.69 g H₂O

7 0
3 years ago
We have learned that the Lewis model portrays a chemical bond as the transfer or sharing of electrons represented as dots. Valen
photoshop1234 [79]

Answer:

According to molecular orbital theory, chemical bond occurs as electrons are able to reduce their energy by entering the resulting molecular orbitals.

Chemical bonds are not located among atoms, they are distributed all over the molecule.

Uses test methods to solve the equation of Schrodinger.

You can never do better than nature, however strong your assumption is. Calculations of minimum energy must be done by software.

3 0
3 years ago
Can anyone help me on this please?
Bad White [126]
This question is testing to see how well you understand the "half-life" of radioactive elements, and how well you can manipulate and dance around them.  This is not an easy question.

The idea is that the "half-life" is a certain amount of time.  It's the time it takes for 'half' of the atoms in any sample of that particular unstable element to 'decay' ... their nuclei die, fall apart, and turn into nuclei of other elements.

Look over the table.  There are 4,500 atoms of this radioactive substance when the time is 12,000 seconds, and there are 2,250 atoms of it left when the time is ' y ' seconds.  Gosh ... 2,250 is exactly half of 4,500 !  So the length of time from 12,000 seconds until ' y ' is the half life of this substance !  But how can we find the length of the half-life ? ? ?

Maybe we can figure it out from other information in the table !

Here's what I found:

Do you see the time when there were 3,600 atoms of it ? 
That's 20,000 seconds.

... After one half-life, there were 1,800 atoms left.
... After another half-life, there were 900 atoms left.
... After another half-life, there were 450 atoms left. 

==>  450 is in the table !  That's at 95,000 seconds.

So the length of time from 20,000 seconds until 95,000 seconds
is three half-lifes.

The length of time is (95,000 - 20,000) = 75,000 sec

                                     3 half lifes = 75,000 sec

Divide each side by 3 :   1 half life = 25,000 seconds

There it is !  THAT's the number we need.  We can answer the question now.

==> 2,250 atoms is half of 4,500 atoms.

==> ' y ' is one half-life later than 12,000 seconds

==> ' y ' = 12,000 + 25,000

         y   = 37,000 seconds  .

Check: 
Look how nicely 37,000sec fits in between 20,000 and 60,000 in the table.

As I said earlier, this is not the simplest half-life problem I've seen.
You really have to know what you're doing on this one.  You can't
bluff through it.


7 0
3 years ago
Describe the changed that happened in the crayon and candle when they cooled after 3 to 5 minutes.​
AleksandrR [38]

Answer:

The change was physical, meaning it went from liquid to solid, or the other way around.

Explanation:

4 0
3 years ago
Other questions:
  • Mixtures can be separated by physical changes. Please select the best answer from the choices provided T F
    7·1 answer
  • Uncooked lean ground beef can contain up to 12% fat by mass. How many grams of fat would be contained in 0.97 lbs of ground beef
    11·1 answer
  • An accounting report that shows the changes in capital during the accounting period is a/an
    5·2 answers
  • What is the maximum number of electrons in oxygen Adam can hold in its outer energy level
    14·1 answer
  • 61. Write formulas for the compounds:
    8·1 answer
  • What is mean by kinetic energy​
    9·1 answer
  • Help bc i need it lol
    13·1 answer
  • Explain why NOBLE gases do not for ions
    11·1 answer
  • Potassium metal reacts with water according to the following balanced equation.
    15·1 answer
  • What substances are produced when an acid reacts with a base?.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!