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3 years ago

URGENT. URGENT. URGENT.

Chemistry

1 answer:

Olin [163]3 years ago

3 0

Answer:

Explanation:

Given data:

Heat required = ?

Mass of sample = 225 g

Initial temperature = 25°C

Final temperature = 60°C

Specific heat capacity of lead = 0.128 j/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 60°C - 25°C

ΔT = 35°C

Q = 225 g × 0.128 j/g°C × 35°C

Q = 1008 j

Given data:

Heat capacity for 1°C = 222 j

Mass of sample = 246 g

Specific heat capacity of sample = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

222 j = 246 g × c × 1°C

c = 222 j / 246 g.°C

c = 0.902 j/g.°C

The given metal is aluminium.

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