The tension in each of the ropes is 625 N.
Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.
Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,
......(1)
Calculate the value of sinθ using the right angled triangles from the diagram.

Substitute the value of sinθ in equation (1) and simplify to obtain T.

Thus the tension in the rope is 625 N.
Answer:
Distance between the charges, r = 0.8 meters
Explanation:
Given that,
Charge 1, 
Charge 2, 
Repulsive force between charges, F = 0.66 N
Let r is the distance between charges. The formula for the electrostatic force is given by :


r = 0.8009 meters
or
r = 0.8 meters
So, the distance between the charges i 0.8 meters. Hence, this is the required solution.
6 cubic feet I’m pretty sure that’s the answer
Answer:
10 Joule
Explanation:
The solution and answer are well written in the Pic above.